It is reported in USA Today that the average flight cost nationwide is $368.88. You have never paid close to that amount and you want to perform a hypothesis test that the true average is actually less than $368.88. What are the appropriate hypotheses for this test?
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It is reported in USA Today that the average flight cost nationwide is $368.88. You have...
It is reported in USA Today that the average flight cost nationwide is $484.314. You have never paid close to that amount and you want to perform a hypothesis test that the true average is actually greater than $484.314. The hypotheses for this situation are as follows: Null Hypothesis: μ ≤ 484.314, Alternative Hypothesis: μ > 484.314. A random sample of 34 flights shows an average cost of $489.228 with a standard deviation of $53.5284. What is the test statistic...
It is reported in USA Today that the average flight cost nationwide is $448.4. You have never paid close to that amount and you want to perform a hypothesis test that the true average is actually greater than $448.4. The hypotheses for this situation are as follows: Null Hypothesis: μ ≤ 448.4, Alternative Hypothesis: μ > 448.4. If the true average flight cost nationwide is $352.63 and the null hypothesis is rejected, did a type I, type II, or no...
It is reported in USA Today that the average flight cost nationwide is $507.93. You have never paid close to that amount and you want to perform a hypothesis test that the true average is actually greater than $507.93. The hypotheses for this situation are as follows: Null Hypothesis: μ ≤ 507.93, Alternative Hypothesis: μ > 507.93. A random sample of 27 flights shows an average cost of $501.435 with a standard deviation of $60.2994. What is the test statistic...
It is reported in USA Today that the average flight cost nationwide is $458.78. You have never paid close to that amount and you want to perform a hypothesis test that the true average is actually less than $458.78. The hypotheses for this situation are as follows: Null Hypothesis: μ ≥ 458.78, Alternative Hypothesis: μ < 458.78. You take a random sample of national flight cost information and perform a one sample mean hypothesis test. You observe a p-value of...
Question 12 (1 point) It is reported in USA Today that the average flight cost nationwide is $380.51. You have never paid close to that amount and you want to perform a hypothesis test that the true average is actually different from $380.51. The hypotheses for this situation are as follows: Null Hypothesis: u = 380.51, Alternative Hypothesis: u 380.51. You take a random sample of national flight cost information and perform a one sample mean hypothesis test. You observe...
Question 17 (1 point) It is reported in USA Today that the average flight cost nationwide is $472.49. You have never paid close to that amount and you want to perform a hypothesis test that the true average is actually less than $472.49. The hypotheses for this situation are as follows: Null Hypothesis: u 2 472.49, Alternative Hypothesis: u < 472.49. If the true average flight cost nationwide is $589.77 and the null hypothesis is rejected, did a type I,...
Question 15 (1 point) Your friend tells you that the proportion of active Major League Baseball players who have a batting average greater than .300 is different from 0.72, a claim you would like to test. The hypotheses here are Null Hypothesis: p = 0.72, Alternative Hypothesis: p ≠ 0.72. If you take a random sample of players and calculate p-value for your hypothesis test of 0.2296, what is the appropriate conclusion? Conclude at the 5% level of significance. Question...
Consumers Energy states that the average electric bill across the state is $123.29. You want to test the claim that the average bill amount is actually different from $123.29. The hypotheses for this situation are as follows: Null Hypothesis: μ = 123.29, Alternative Hypothesis: μ ≠ 123.29. You complete a randomized survey throughout the state and perform a one-sample hypothesis test for the mean, which results in a p-value of 0.3178. What is the appropriate conclusion? Conclude at the 5%...
Part A: A restaurant wants to test a new in-store marketing scheme in a small number of stores before rolling it out nationwide. The new ad promotes a premium drink that they want to increase the sales of. 5 locations are chosen at random and the number of drinks sold are recorded for 2 months before the new ad campaign and 2 months after. The average difference in the sales quantity (after - before) is -42.749 with a standard deviation...
Question 12 (1 point) Consumers Energy states that the average electric bill across the state is $108.57. You want to test the claim that the average bill amount is actually greater than $108.57. The hypotheses for this situation are as follows: Null Hypothesis: μ ≤ 108.57, Alternative Hypothesis: μ > 108.57. You complete a randomized survey throughout the state and perform a one-sample hypothesis test for the mean, which results in a p-value of 0.6273. What is the appropriate conclusion?...