Question

In a program designed to help patients stop smoking, 245 patients were given sustained care, and 83.8 % of them were no longer smoking after one month. Use a 0.10 significance level to test the claim that 80 % of patients stop smoking when given sustained care.

1. Identify the null and alternative hypothesis for this test.

2. Identify the test statistics for this hypothesis

3. The p- Value

can you show me how to do this on ti 84 calculator please??

Answer 1

Solution:-

given, n=245,

therefore, x=205

1)Null and Alternative hypothesis is,

H​​​​​​0:p=0.80

H​​​​​​a:p0.80

2) Test statistics,

z=1.44

3) p-value=0.1506

Ti-84 path: STAT>TESTS>5:1-PropZTest>enter data and calculate.

Here, p-value>

Hence, we fail to reject null hypothesis.