Question

Assistance with C coding.

Hi, so I require assistance upon a C lab assignment. Time is very much of the essence. Write a C code, complete with the main driver and corresponding functions, that asks the user for a zip code and prints the bar code. Use : for half bars, | for full bars. For example, 95014 becomes ||:|:::|:|:||::::::||:|::|:::|||

Time is very much limited!

Answer 1

C Code:

#include <stdio.h>

int sumOfDigits(input){

    if(input/10 == 0){

        return input;

    }

    return input%10 + sumOfDigits(input/10);

}

int checkNumber(int n){

    if (n == 0 || n % 10 == 0){

        return 0;

    }

    return ((n % 10) - 10) * (-1);

}

void printDigit(int n){

    if(n==1){

        printf(":::||");

    }

    if(n==2){

        printf("::|:|");

    }

    if(n==3){

        printf("::||:");

    }

    if(n==4){

        printf(":|::|");

    }

    if(n==5){

        printf(":|:|:");

    }

    if(n==6){

        printf(":||:");

    }

    if(n==7){

        printf("|:::|");

    }

    if(n==8){

        printf("|::|:");

    }

    if(n==9){

        printf("|:|::");

    }

    if(n==0){

        printf("||:::");

    }

}

void printBarCode(int zipCode){

    int n = 1000000;

    printf("|");

    while (n / 10 != 0){

        n /=10;

        printDigit(zipCode / n % 10);

    }

    printf("|");

}

int main(){

    int input, n, zipcode, sum;

    printf("Enter a zip code: ");

    scanf("%d", &input);

    sum = sumOfDigits(input);

    zipcode = input *10 + checkNumber(sum);

    printf("Zip in Barcode\n");

    printBarCode(zipcode);

    return 0;

}

Output:

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