What is ΔHsys for a reaction at 16.2 °C with ΔSsurr = 389 J mol-1 K-1 ? Express your answer in kJ mol-1 .
ΔSsurr = 389 J mol-1 K-1
So,
ΔSsys = -ΔSsurr
= -389 J mol-1 K-1
T = 16.2 oC
= (16.2 + 273.1) K
= 289.3 K
Now use:
ΔSsys = ΔHsys / T
-389 J mol-1 K-1 = ΔHsys / 289.3 K
ΔHsys = -112538 J mol-1
ΔHsys = -112.5 KJ mol-1
Answer: -112.5 KJ mol-1
What is ΔHsys for a reaction at 16.2 °C with ΔSsurr = 389 J mol-1 K-1...
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