Solve the problem below using the intuitive least cost method and answer the following: Cranbury Plainfield...
Solve the problem below using the intuitive least cost method and answer the following:
| Cranbury | Plainfield | Saddle Brook | Supply | |
| Gallway | $31 | $18 | $35 | 300 |
| Hendron | $23 | $21 | $27 | 250 |
| Vienna | $22 | $25 | $18 | 275 |
| Demand | 300 | 225 | 300 |
What is the maximum quantity that can be shipped from Gallway to Plainfield? [ Select ] ["$18", "$21", "$25", "300", "225"]
What is the maximum quantity that can be shipped from Vienna to Saddle Brook? [ Select ] ["300", "275", "$25", "$18", "$22"]
What is the maximum quantity that can be shipped from Hendron to Cranbury? [ Select ] ["$21", "$27", "250", "$23", "300"]
What will be the cost of this assignment?
Homework Answers
Maximum quantity shipment form Gallway to Plainfield is 225 (Demand = 225 and supply = 300, So, 225 units can be supplied)
Maximum quantity shipment from Vienna to Saddl Brook is 275 (Demand =300 and supply= 275. So, 275 units can be supplied)
Maximum quantity shipment from Hendron to Cranbury is 250 (Demand = 200 and supply = 250. So, 250 units can be supplied.
The cost of this assignment is $17175
| Cranbury | Plainfield | Saddle Brook | Supply | ||
| Gallway | $31 (50) | $18 (225) | $35(25) | 300 | |
| Handron | $23 (250) | $21 | $27 | 250 | |
| Vienna | $22 | $25 | $18 (275) | 275 | |
| Demand | 300 | 225 | 300 | 825 | |
Total cost of assignment = ($31*50)+($18*225)+($35*25)+($23*250)+($18*275)
= $17175
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plz all the question and how and why was it solve this way thanks a lot...
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plz all the question and how and why was it solve this way
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