1) An object with height of 2.5 cm lies 10 cm in front of a lens with focal length of 6 cm.
c) Suppose that this image serves as the object for a second lens that has a focal length of + 4 cm. The second lens is placed 6 cm beyond the image serving as its object. Where is the image formed by this second lens?
d) What is the magnification produced by the second lens?
An object with height of 2.5 cm lies 10 cm in front of a lens with focal length of 6 cm. Calculate the image distance for this object. b. What is the magnification of this object?
An object of height 2.8 cm is placed 27 cm in front of a diverging lens of focal length 16 cm. Behind the diverging lens, and 11 cm from it, there is a converging lens of the same focal length.Part (a) Find the location of the final image, in centimeters beyond the converging lens. Part (b) What is the magnification of the final image? Include its sign to indicate its orientation with respect to the object.
Problem 3: An object of height
2.8 cm is placed 26 cm in front of a diverging lens of focal length
16 cm. Behind the diverging lens, and 11 cm from it, there is a
converging lens of the same focal length.
a) Find the location of the final image, in centimeters beyond
the converging lens (such that a negative answer would indicate the
final image is on the same side of the converging lens as the
object).
b) What...
Use the thin lens equation to solve problems 14 –18. 14. An object is 10 cm high and is placed 20 cm in front of a converging lens of focal length 20 cm. Determine the image distance, the image height and the magnification. 15. An object is 10 cm high and is placed 16 cm in front of a converging lens of focal length 20 cm. Determine the image distance, the image height and the magnification. 16. An object is...
(10%) Problem 10: An object of height 2.8 cm is placed 28 cm in front of a diverging lens of focal length 16 cm. Behind the diverging lens, and 13 cm from it, there is a converging lens of the same focal length. 25% Part (a) Find the location of the image created by the diverging lens in centimeters relative to the location of that lens. Use the standard sign convention such that your answer will be negative if the...
(4%) Problem 18: An object of height 2.9 cm is placed 29 cm in front of a diverging lens of focal length 15 cm. Behind the diverging lens, and 11 cm from it, there is a converging lens of the same focal length. 50% Part (a) Find the location of the final image, in centimeters beyond the converging lens. 50% Part (b) What is the magnification of the final image? Include its sign to indicate its orientation with respect to...
An object is placed 6.0 cm in front of a lens of focal length 5.0 cm. Another lens of focal length 4.0 cm is placed 2.4 cm behind the first lens. (a) Where is the final image? distance cm location ---Select--- behind the second lens in front of the second lens, but between lenses in front of the first lens Is the image real or virtual? virtualreal (b) What is the overall magnification?
A converging lens has a focal length of 40 cm. An object, of height 10 cm from optic axis to its tip, is placed 60 cm in front of the lens. Draw a ray diagram to get location of image and magnification. Then use the lens formula to make your answer precise.
Use ray diagrams to solve problems 10 –13. 10. An object is 10 cm high and is placed 30 cm in front of a converging lens of focal length 20 cm. Determine the image distance, the image height and the magnification. 11. An object is 10 cm high and is placed 20 cm in front of a converging lens of focal length 20 cm. Determine the image distance, the image height and the magnification. 12. An object is 10 cm...
1. A 5.0 cm high object is placed 10.0 cm from a converging lens of focal length 25.0 cm. What is the height of the image formed by the lens? a. 1.67 cm b. 8.35 cm c. 5.38 cm d. 3.85 cm 2. A 2.0 cm tall object is 30.0 cm in front of a diverging lens of focal length 15.0 cm. What is the magnification produced by the lens? a. 0.23 b. 0.33 c. 1.0 d. 0.25