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You used a survey to estimate the number of households eligible for home-delivered meals, but mot...

You used a survey to estimate the number of households eligible for home-delivered meals, but mot getting them; you used telephone screening to find eligible households. Assume that you have randomly drawn a sample and collected data on 800 units.

12% of elderly households in the sample are eligible, but not getting meals. There are 1.06 million elderly households in the state, all of which are in the sample frame. What is the margin of error, at 95% confidence, associated with our estimate of 127,200? What are the confidence intervals at this margin of error?

(Write as whole number OR decimal)

Note: See MoSE equation

math   Statistics-And-Probability   
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Answer #1

Given : Sample size=n=800

Sample proportion=p=12%=0.12

q=1-p=0.88

Significance level=0.05

The margin of error is ,

Therefore , the 95% confidence interval is ,

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