Design a 7 segment display decoder using a 16:1 multiplexer (no more than 7 chips). The...
Design a 7 segment display decoder using a 16:1 multiplexer (no more than 7 chips). The output of the 7 segment display must be 0-F in hex. Please use Karnaugh-maps if necessary. Thank you kindly!
Homework Answers
Common Cathode Seven segment Truth Table is shown below:
|
DIGIT |
INPUTs |
COMMON CATHODE SEVEN SEGMENT |
|||||||||
|
D3 |
D2 |
D1 |
D0 |
a |
b |
c |
d |
e |
f |
g |
|
|
0 |
0 |
0 |
0 |
0 |
1 |
1 |
1 |
1 |
1 |
1 |
0 |
|
1 |
0 |
0 |
0 |
1 |
0 |
1 |
1 |
0 |
0 |
0 |
0 |
|
2 |
0 |
0 |
1 |
0 |
1 |
1 |
0 |
1 |
1 |
0 |
1 |
|
3 |
0 |
0 |
1 |
1 |
1 |
1 |
1 |
1 |
0 |
0 |
1 |
|
4 |
0 |
1 |
0 |
0 |
0 |
1 |
1 |
0 |
0 |
1 |
1 |
|
5 |
0 |
1 |
0 |
1 |
1 |
0 |
1 |
1 |
0 |
1 |
1 |
|
6 |
0 |
1 |
1 |
0 |
1 |
0 |
1 |
1 |
1 |
1 |
1 |
|
7 |
0 |
1 |
1 |
1 |
1 |
1 |
1 |
0 |
0 |
0 |
0 |
|
8 |
1 |
0 |
0 |
0 |
1 |
1 |
1 |
1 |
1 |
1 |
1 |
|
9 |
1 |
0 |
0 |
1 |
1 |
1 |
1 |
1 |
0 |
1 |
1 |
|
A |
1 |
0 |
1 |
0 |
1 |
1 |
1 |
0 |
1 |
1 |
1 |
|
B |
1 |
0 |
1 |
1 |
0 |
0 |
1 |
1 |
1 |
1 |
1 |
|
C |
1 |
1 |
0 |
0 |
1 |
0 |
0 |
1 |
1 |
1 |
0 |
|
D |
1 |
1 |
0 |
1 |
0 |
1 |
1 |
1 |
1 |
0 |
1 |
|
E |
1 |
1 |
1 |
0 |
1 |
0 |
0 |
1 |
1 |
1 |
1 |
|
F |
1 |
1 |
1 |
1 |
1 |
0 |
0 |
0 |
1 |
1 |
1 |
Since 7 no's of 16 to 1 Mux is allowed, inputs from truth table can be directly mapped to multiplexer inputs as shown below without K Map Simplification.
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