Question

According to a recent survey of the 18​,000 funeral homes of a certain​ nation, funeral homes...

According to a recent survey of the 18​,000 funeral homes of a certain​ nation, funeral homes collected an average of​6,700 per​ full-service funeral last year. A random sample of 36 funeral homes reported revenue data for the current year. Among other​ measures, each reported its average fee for a​ full-service funeral. These data​ (in thousands of​ dollars) are shown in the accompanying table. Complete parts a through c below.\

7.4

9.4

5.2

8.5

7.7

6.3

6.2

8.3

6.4

11.6

6.3

5.8

7.2

6.1

5.2

6.5

6.1

7.5

7.2

6.4

6.3

5.2

6.9

5.6

9.3

7.5

7.4

5.8

7.1

5.9

6.9

7.5

5.9

5.4

7.7

6.9

a. What are the appropriate null and alternative hypotheses to test whether the average​ full-service fee of funeral homes this year exceeds ​$ 6,700​?

A. H0​: μ=6.7

Ha​: μ > 6.7

B. H0​: μ ≠ 6.7

Ha​:μ = 6.7

C. H0​: μ = 6.7

Ha​: μ < 6.7

D. H0​: μ = 6.7

Ha​:μ ≠ 6.7

b. Conduct the test at α = 0.10. Do the sample data provide sufficient evidence to conclude that the average fee this year is higher than last​ year?

Find the test statistic.

z = ___________ ​(Round to two decimal places as​ needed.)

Find the​ p-value.

​p- value = _________ ​(Round to three decimal places as​ needed.)

State the result of this test.

A. H0 is rejected. There is insufficient evidence at the α=0.10 level of significance to conclude that the average fee this year is higher than last year.

B. H0 is not rejected. There is sufficient evidence at the α=0.10 level of significance to conclude that the average fee this year is higher than last year.

C. H0 is not rejected. There is insufficient evidence at the α=0.10 level of significance to conclude that the a fee this year is higher than last year.

D. H0 is rejected. There is sufficient evidence at the α=0.10 level of significance to conclude that the average fee this year is higher than last year.

c. In conducting the​ test, was it necessary to assume that the population of average​ full-service fees was normally​ distributed? Justify your answer.

A. ​Yes, because the sample size is greater than 30.

B. ​No, because the sample size is greater than 30.

C. ​Yes, because the sample size is less than 40.

D. ​No, because the sample size is less than 40.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Solution:-

a) (A) State the hypotheses. The first step is to state the null hypothesis and an alternative hypothesis.

Null hypothesis: u < 6.70
Alternative hypothesis: u > 6.70

Note that these hypotheses constitute a one-tailed test.

Formulate an analysis plan. For this analysis, the significance level is 0.10. The test method is a one-sample z-test.

Analyze sample data. Using sample data, we compute the standard error (SE), z statistic test statistic (z).

SE = s / sqrt(n)

S.E = 0.2581

z = (x - u) / SE

z = 0.943

where s is the standard deviation of the sample, x is the sample mean, u is the hypothesized population mean, and n is the sample size.

The observed sample mean produced a z statistic test statistic of 0.943.

Thus the P-value in this analysis is 0.173.

Interpret results. Since the P-value (0.173) is greater than the significance level (0.10), we cannot reject the null hypothesis.

(C) H0 is not rejected. There is insufficient evidence at the α=0.10 level of significance to conclude that the a fee this year is higher than last year.

c) (A) Yes, because the sample size is greater than 30.

Add a comment
Know the answer?
Add Answer to:
According to a recent survey of the 18​,000 funeral homes of a certain​ nation, funeral homes...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • According to a recent survey of the 18​,000 funeral homes of a certain​ nation, funeral homes...

    According to a recent survey of the 18​,000 funeral homes of a certain​ nation, funeral homes collected an average of ​$6,700 per​ full-service funeral last year. A random sample of 36 funeral homes reported revenue data for the current year. Among other​ measures, each reported its average fee for a​ full-service funeral. These data​ (in thousands of​ dollars) are shown in the accompanying table. Complete parts a through c below. Table 7.5 9.1 5.4 8.6 7.7 6.3 5.9 8.6 6.5...

  • the resull. 12 Revenue for National Funeral Di n's 19,000 funeral hon er full-service funeral a...

    the resull. 12 Revenue for National Funeral Di n's 19,000 funeral hon er full-service funeral a full-service funeral. According to the al Directors Association (NFDA), the na- eral homes collected an average of $7,180 funeral in 2014 (www.nfda.org). A random funeral homes reported revenue data for the tron's z sample of 36 fund current year. Among other measures, each reported its average fee for a full-service funeral. These data (in thou- sands of dollars) are shown in the following table....

  • The desired percentage of SiO2 in a certain type of aluminous cement is 5.5. To test whether the ...

    The desired percentage of SiO2 in a certain type of aluminous cement is 5.5. To test whether the true average percentage is 5.5 for a particular production facility, 16 independently obtained samples are analyzed. Suppose that the percentage of SiO2 in a sample is normally distributed with σ = 0.32 and that x = 5.22. (Use α = 0.05.) (a) Does this indicate conclusively that the true average percentage differs from 5.5? State the appropriate null and alternative hypotheses. H0:...

  • According to a survey, the average American person reads for 3 hours per week. To test...

    According to a survey, the average American person reads for 3 hours per week. To test if the amount of reading in Chicago is more than the national average, a researcher decides to do a hypothesis test, at a 5% significance level. She surveys 17 Chicagoans randomly and asks them about their amount of TV each week, on average. From the data, the sample mean time is 3.4 hours per week, and the sample standard deviation (s) is 0.8 hours....

  • Exercise 9-15 Algo Consider the following hypotheses: H0: μ ≥ 130 HA: μ < 130 A...

    Exercise 9-15 Algo Consider the following hypotheses: H0: μ ≥ 130 HA: μ < 130 A sample of 74 observations results in a sample mean of 125. The population standard deviation is known to be 31. (You may find it useful to reference the appropriate table: z table or t table) a-1. Calculate the value of the test statistic. (Negative value should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places and final answer...

  • In order to conduct a hypothesis test for the population mean, a random sample of 24...

    In order to conduct a hypothesis test for the population mean, a random sample of 24 observations is drawn from a normally distributed population. The resulting sample mean and sample standard deviation are calculated as 6.3 and 2.5, respectively. (You may find it useful to reference the appropriate table: z table or t table). H0: μ ≤ 5.1 against HA: μ > 5.1 a-1. Calculate the value of the test statistic. (Round all intermediate calculations to at least 4 decimal...

  • Only 18% of registered voters voted in the last election. Will voter participation increase for the...

    Only 18% of registered voters voted in the last election. Will voter participation increase for the upcoming election? Of the 352 randomly selected registered voters surveyed, 77 of them will vote in the upcoming election. What can be concluded at the α= 0.05 level of significance? For this study, we should use Select an answer t-test for a population mean or z-test for a population proportion The null and alternative hypotheses would be:    H0:? μ p  Select an answer ≠...

  • 18% of all college students volunteer their time. Is the percentage of college students who are...

    18% of all college students volunteer their time. Is the percentage of college students who are volunteers larger for students receiving financial aid? Of the 301 randomly selected students who receive financial aid, 72 of them volunteered their time. What can be concluded at the αα = 0.10 level of significance? For this study, we should use Select an answer t-test for a population mean z-test for a population proportion The null and alternative hypotheses would be:    H0:H0:  ? p...

  • The lengths of major league baseball games are approximately normally distributed and average 2 hours and...

    The lengths of major league baseball games are approximately normally distributed and average 2 hours and 50.1 minutes (170.1 minutes), with a population standard deviation of 18 minutes. It has been claimed that New York Yankee baseball games last, on the average, longer than the games of the other major league teams. To test the truth of this statement, a sample of eight Yankee games were randomly identified and the "time of the game" (in minutes) for each obtained. 199...

  • What percentage of the population live in their state of birth? According to the U.S. Census Bureau's American Community Survey, the figure ranges from 25% in Nevada to 78.7% in Louisiana.† The av...

    What percentage of the population live in their state of birth? According to the U.S. Census Bureau's American Community Survey, the figure ranges from 25% in Nevada to 78.7% in Louisiana.† The average percentage across all states and the District of Columbia is 57.7%. The data in the DATAfile HomeState are consistent with the findings in the American Community Survey. The data are for a random sample of 120 Arkansas residents and for a random sample of 180 Virginia residents....

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT