Question

Determine the concentration of 20.0 mL of the sulphuric acid when 1.00 mol/L sodium hydroxide is used as the titrant.

Answer 1

This is an acid base neutralization reaction. In the problem volume of the NaOH is missed it is taken as = 10 ml

H2SO4 -----> 2H⁺ + SO4^{​​​​-2}

Therefore H2SO4 is a dibasic acid

So,

no.of moles of Acid ( H2SO4 ) = 2 x [ no.of moles of Base ( NaOH ) ]

2 x (Molarity x Volume ) /1000 = ( Molarity x Volume ) / 1000

2 x ( a x 20 ) = ( 1 M x 10 )

40 a = 10

a = 0.25 M

Therefore the concentration of H2SO4 = 0.25 M