The mean price for used cars is $10,312. A manager of a Kansas City used car dealership reviewed a sample of 50 recent used car sales at the dealership in an attempt to determine whether the population mean price for used cars at this particular dealership differed from the national mean. The prices for the sample of 50 cars are contained in the Excel Online file below. Construct a spreadsheet to answer the following questions. Open spreadsheet a. Formulate the hypotheses that can be used to determine whether a difference exists in the mean price for used cars at the dealership. b. What are the test statistic and the p -value? Do not round intermediate calculations. t- (to 3 decimals) p-value (to 4 decimals) c. At a=0.01 what is your conclusion? the null hypothesis. We have evidence to conclude that the population mean price at this dealership differs from the national mean price of $10,312.
11611 |
7971 |
12838 |
11109 |
6474 |
6320 |
9523 |
6411 |
12805 |
9688 |
9478 |
10149 |
10176 |
11463 |
7084 |
8906 |
9508 |
9386 |
6506 |
8864 |
8447 |
7165 |
9591 |
7075 |
8431 |
6267 |
11309 |
8527 |
10488 |
9033 |
12180 |
6692 |
9622 |
7949 |
12730 |
9136 |
12588 |
12809 |
11024 |
11054 |
9743 |
10136 |
12629 |
8361 |
12188 |
11103 |
10578 |
7561 |
6623 |
8151 |
Given:
= 10.312, n = 50, = 9509.20, SD(S) = 2018.76, = 0.01
a)
Hypothesis:
Ho: = 10312
Ha: 10312
b)
Test statistic:
Degree of freedom = n-1 = 50-1 = 49
P-value = 0.0071 ....................Using t table
C)
Conclusion:
P-value < , i.e. 0.0071 < 0.05, That is Reject Ho at 1% level of signfiiacnce.
We have evidence to conclude that the population mean price at this dealership differs from the national mean price of $10,312.
We were unable to transcribe this image
We were unable to transcribe this image
We were unable to transcribe this image
We were unable to transcribe this image
We were unable to transcribe this image
We were unable to transcribe this image
X-4 t=slv 9509.20 - 10312 F= -2.812 2018.76/50
We were unable to transcribe this image
The mean price for used cars is $10,312. A manager of a Kansas City used car...
The mean price for used cars is $10,206. A manager of a Kansas City used car dealership reviewed a sample of 50 recent used car sales at the dealership in an attempt to determine whether the population mean price for used cars at this particular dealership differed from the national mean. The prices for the sample of 50 cars are contained in the Excel Online file below. Construct a spreadsheet to answer the following questions. . What are the test...
Screen Shot 2019-09-24 at 9.26.08 PM Q Search 13114 12490 11941 9011 6787 9203 The mean price for used cars is $10,619. A manager of a Kansas City used car dealership reviewed a sample of 50 recent used car sales at the dealership in an attempt to determine whether the population mean price for used cars at this particular dealership differed from the national mean. The prices for the sample of 50 cars are contained in the Excel Online file...
Sales records indicate that the selling price of used cars at a large car dealership are skewed right, with a mean of $17000 and a standard deviation of $11000 Explain whether Table Z (the normal distribution table) could be used to find the probability that a single used car at this dealership would sell for less than $20000 For a random sample of 70, the mean for the sampling distribution of average price would be and the standard deviation would...
4) A used car dealer says that the mean price of a 2019 Honda CR-V is more than $24,443. You suspect this claim is incorrect and find that a random sample of 14 similar vehicles has a mean price of $25,050 and a standard deviation of $1084. Is there enough evidence to reject the dealer's claim at a = 0.02? Assume the price of used cars is normally distributed. (18 points total) Step 1: Write the hypothesis statements, identify which...