Suppose scores of a standardized test are normally distributed and have a known population standard deviation...
Suppose scores of a standardized test are normally distributed and have a known population standard deviation of 8 points and an unknown population mean. A random sample of 25 scores is taken and gives a sample mean of 93 points.
Find the margin of error for a confidence interval for the population mean with a 98% confidence level.
| z0.10 | z0.05 | z0.025 | z0.01 | z0.005 |
|---|---|---|---|---|
| 1.282 | 1.645 | 1.960 | 2.326 | 2.576 |
You may use a calculator or the common z values above.
- Round the final answer to two decimal places.
Homework Answers
Solution: Given that mean = 93, population standard deviation = 8, n = 25
98% Confidence level for Z = 2.326 (by using above table)
margin of error = Z*σ/sqrt(n)
= 2.326*8/sqrt(25)
= 3.7216
= 3.72 (rounded)
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