The formula used to compute a large-sample confidence interval for p is
p̂ ± (z critical value)
|
What is the appropriate z critical value for each of the following confidence levels? (Round your answers to two decimal places.)
a) 85%
solution:
At 85% confidence level the z is ,
= 1 - 85% = 1 - 0.85 = 0.15
/ 2 = 0.15/ 2 = 0.075
Z/2 = Z0.075 =1.44 ( Using z table )
The formula used to compute a large-sample confidence interval for p is p̂ ± (z critical...
The formula used to compute a large-sample confidence interval for p is p̂ ± (z critical value) p̂(1 − p̂) n What is the appropriate z critical value for each of the following confidence levels? (Round your answers to two decimal places.) 87%
-15 POINTS PODSTAT6 9.E.012. MY NOTES ASK YOUR TEACHER The formula used to calculate a large-sample confidence interval for p is Ộ + (2 critical value) (1 - ). What is the appropriate z critical value for each of the following confidence levels? (Round your answers to two decimal places.) (a) 95% (b) 90% (c) 99% (d) 80% (e) 91% You may need to use the appropriate table in the appendix or technology to answer this question. Need Help? Read...
Using the formula ,compute a 95% confidence interval for a population proportion given the sample proportion is 0.24 and the sample size is 1014. Round your answers to 4 decimal places, e.g. 0.7523. 0.0263
a. You wish to compute the 95% confidence interval for the population proportion. How large a sample should you draw to ensure that the sample proportion does not deviate from the population proportion by more than 0.12? No prior estimate for the population proportion is available. Round intermediate calculations to at least 4 decimal places and "z" value to 3 decimal places. Round up your answer to the nearest whole number.) Sample Size - b. A business student is interested...
A 90% confidence interval for p is given as (0.37,0.63). How large was the sample used to construct this interval? n(Round up to the nearest observation.)
A 95% confidence interval for p is given as (0.27,0.53). How large was the sample used to construct this interval? n(Round up to the nearest observation.)
Calculate the margin of error and construct a confidence interval for the population proportion using the normal approximation to the p̂ p̂ -distribution (if it is appropriate to do so). Standard Normal Distribution Table a. p̂ =0.85, n=140, α =0.2 p̂ =0.85, n=140, α =0.2 E=E= Round to four decimal places Enter 0 if normal approximation cannot be used < p < < p < Round to four decimal places Enter 0 if normal approximation cannot be used b. p̂ =0.3, n=160, α =0.2 p̂ =0.3, n=160, α =0.2...
For a population, N=16,000 and p= 0.22. Find the z value for p̂ = 0.26 for n=50. Round your answer to two decimal places. Z=
A 98% confidence interval for a population proportion is given as 0.531 < p < 0.693. Round your answers to 3 decimal places. (a) Calculate the sample proportion. p̂ = (b) Calculate the margin of error. E =
A 95% confidence interval for p is given as (0.19,0.41). How large was the sample used to construct this interval? (Round up to the nearest observation.)