How many grams of CaF2 would be needed to produce 1.07 moles of F2?
Molar mass of CaF2 = 78.07 g/mol
For 1 mol of F2, 1 mole of CaF2 is required
for 1.07
moles of F2, 1.07 Moles of CaF2 is required
required
CaF2= (1.07 mol)×(78.07 g/mol)
=83.5 grams
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3H2
+ N2 -> 2NH3
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