The molality of calcium chloride (CaCl2) in an aqueous solution is 3.37 m. What is mole fraction of the solute? Keep 3 significant figures in your answer.
mole fraction of the solute = 0.0572
Explanation
molality of CaCl2 = 3.37 m
This means 3.37 moles of CaCl2 is dissolved in 1 kg water
mass of water = 1kg = 1000 g
moles of water = (mass of water) / (molar mass of water)
moles of water = (1000 g) / (18.0 g/mol)
moles of water = 55.5 mol
Total moles = moles CaCl2 + moles of water
Total moles = 3.37 mol + 55.5 mol
Total moles = 58.9 mol
mole fraction of CaCl2 = (moles of CaCl2) / (total moles)
mole fraction of CaCl2 = (3.37 mol) / (58.9 mol)
mole fraction of CaCl2 = 0.0572
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