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According to Chebyshev's Theorem, at least what proportion of the data will be within 1.2 standard...

According to Chebyshev's Theorem, at least what proportion of the data will be within 1.2 standard deviation distance about the mean? 27% 30% 61% 68% 69%

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Answer #1

Answer

we know the formula

Area within k standard deviation =1 - 1/k^2

we have to find area or proportion within 1.2, so putting k = 1.2

we get

proportion = 1 - 1/1.2^2

= 1 - 0.6944

= 0.3056

= 0.3056*100

= 30.56%

= 30% (approx)

option B is correct (30%)

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