According to Chebyshev's Theorem, at least what proportion of the data will be within 1.2 standard deviation distance about the mean? 27% 30% 61% 68% 69%
Answer
we know the formula
Area within k standard deviation =1 - 1/k^2
we have to find area or proportion within 1.2, so putting k = 1.2
we get
proportion = 1 - 1/1.2^2
= 1 - 0.6944
= 0.3056
= 0.3056*100
= 30.56%
= 30% (approx)
option B is correct (30%)
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