(78.7÷88.529) +351.05
I cannot figure out the Sig Figs in this solution
In division product should have the significant figure of the entity with least significant figure.
78.7÷88.529=0.9
In addition least decimals to be considered.
0.9+351.05=351.95=351.9
(78.7÷88.529) +351.05 I cannot figure out the Sig Figs in this solution
2) a) Using the correct number of sig, figs., calculate the pH of a solution that has [H3O1 4.3 x 10-8 M (I pt.) b)) Classify this solution as acidic, basic, or neutral. (1 pt.)
Round the value 875.2763 to 1) 5 sig figs 2) 3 sig figs 3) 2 sig figs 4) 1 sig fig
Identify the number of significant figures (sig figs) in each of these values. 1 sig fig 2 sig figs 3 sig figs 4 sig figs 5 sig figs 200 0.020 2300 7.000 11020 0.05 89122 Answer Bank Incorrect
0.0411 mol of glucose in 85.2 mL of solution using 3 sig figs Thank you
Identify the number of significant figures (sig figs) in each of these values. Note: If any part of this question is answered incorrectly, a single red X will appear. 1 sig fig 2 sig figs 0.05 0.060 0.160 3 sig figs 4 sig figs 5 sig figs 70.0 8090.0 0.08006 4.050
The correct solution is 2.94% but I cannot figure out how to get that solution. Please help. Thank you so much. You invest $3,200 in a savings account on January 1, 2004. On December 31, 2004, the account has accumulated to $3,294.08. What is the annual interest rate? CE)
I cannot figure out part B
I cannot seem to figure this reaction out.
What is the [OH-] in a solution with a pH of 2.50? (answer to 3 sig figs)
calculate the equilibrium molarity of aqueous Ag+ ion. round to two sig figs For the aqueous [ Ag(NH;)]* complex K; = 1.7x 10' at 25 °C. Suppose equal volumes of 0.0082 M AgNO, solution and 0.20 M NH, solution are mixed. Calculate the equilibrium molarity of aqueous Aglon. Round your answer to 2 significant digits. OM x 5 ?