When you irradiate a metal with light of wavelength 441 nm in an investigation of the...
When you irradiate a metal with light of wavelength 441 nm in an investigation of the photoelectric effect, you discover that a potential difference of 1.07 V is needed to reduce the current to zero.
What is the energy of a photon of this light in electron volts?
energy of a photon:
Find the work function of the irradiated metal in electron volts.
work function:
Homework Answers
Here ,
wavelength = 441 nm
energy of photon , E = h * c/wavelength*e
E = 6.626 *10^-34 * 3 *10^8/(1.602 *10^-19 * 441 *10^-9)
E = 2.81 eV
the energy of photon is 2.81 eV
for the work function ,
work function = 2.81 - 1.07
work function = 1.74 eV
the work function is 1.74 eV
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