Question

USE C++ TO DEVELOP THE CODE. THANKS IN ADVANCE

create an array of strings with a size of 10.
explain the story to the player, whatever story you wish to tell.
the player starts with 3 items.
over the course of several adventures, 
1.  the player gains 3 items and has to name each of them.
for example: BunnySword or FlameGuitar
- because of cin limitations, the name can only be one word.
2.  the player uses 1 item, making it go away.
3. at each change in inventory - show the changes with a for loop that ignores strings that have "" no characters.   
For the final challenge, the player must give up their most treasured item to the bridge troll (or similar) to get past the bridge.
The player will have to search for that item inside of a for loop.

Beyond the Requirements

1. Create dialogue that makes the program feel more intuitive
2. Use a while or do-while loop to ensure that the player successfully finds an item before moving past the bridge.

Answer 1

CODE:

#include <iostream>

#include <string>

using namespace std;

// print the string array

void print(string player[]){

  cout<<"\nYour current items are:\n";

  for(int i=0;i<10;i++){

    if(!player[i].empty())

    cout<<"\n"<<player[i]<<"\n";

  }

}

// delete one item from the array

void loose(string player[]){

  cout<<"\nLost 1 item\n";

  // loose one item

  for(int i=0;i<10;i++){

    if(!player[i].empty())

    {

      player[i].clear();

      break;

    }

  }

  print(player);

}

// add 3 items in the array

void gain(string player[]){

  cout<<"You gained 3 items\n";

  // gain 3 items

  int n=3;

  string item;

  while(n--){

    cout<<"Enter item name:\n";

    cin>>item;

    for(int i=0;i<10;i++){

      if(player[i].empty()){

        player[i]=item;

        break;

      }

    }

  }

  print(player);

}

int main() {

  string player[10];

  // hard coding 3 items in the start of the game

  player[0]="BunnySword";

  player[1]="Ironman";

  player[2]="ninja";

  char ch;

  

  do{

    gain(player);

    loose(player);

    cout<<"\nDo you wish to continue the adventure(Y/N): "<<endl;

    cin>>ch;

  }while(ch=='Y' || ch=='y');

}

OUTPUT:

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