A colorblind woman and a man with normal vision have 2 colorblind sons and 4 normal...
A colorblind woman and a man with normal vision have 2 colorblind sons and 4 normal vision daughters. What is the probability that their next child will be a colorblind son?
Homework Answers
The colorblindness is X - linked recessive trait. A woman having colorblindness trait can pass to the son and male offspring are affected. The colorblindness trait from father is passed to daughters who can be carriers. The women are affected when they receive recessive trait both from mother and father.
The genotype of colorblind woman: Xc Xc
The genotype of colorblind father: Xc Y
The genotype of father with normal vision: XC Y
The colorblind woman marries man with normal vision:
XcXc x XCY
| male/ female | XC | Y |
| Xc | XCXc | XcY |
| Xc | XCXc | XcY |
Therefore, the offspring produced are carrier daughters (50%) and affected sons (50%) and the phenotypic ratio is 1:1. Therefore, the probability of next child a colorblind son would be 50%
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