Suppose two 100 g are suspended at the 30 cm and 40 cm marks. Calculate the mass that must be suspended at 90 cm mark in order for the meter stick to balance. Write the sum of torques equation.
Suppose two 100 g are suspended at the 30 cm and 40 cm marks. Calculate the...
A new meter stick has dimensions of 100 cm by 2.5 cm by 0.60 cm and has a total mass of 70.0 grams. Assume the density of the stick is uniform throughout. a.) What is the linear mass density of the meter stick? b.) If somebody drills 0.50 cm diameter holes at the 60, 70, 80 and 90 cm marks, where will the new center of mass for the meter stick be located? c.) If a 50 gram mass is...
A new meter stick has dimensions of 100 cm by 2.5 cm by 0.60 cm and has a total mass of 70.0 grams. Assume the density of the stick is uniform throughout. a.) What is the linear mass density of the meter stick? b.) If somebody drills 0.50 cm diameter holes at the 60, 70, 80 and 90 cm marks, where will the new center of mass for the meter stick be located? c.) If a 50 gram mass is...
Procedure 1, 2, 3 Mass of a clamp: 21.5 True mass of meter stick: _133.6 g Center of mass of meter stick: _50 cm True weight of unknown mass: _212.99_ Procedure 4 Position of the 100-g mass: 10.0 cm Position of equilibrium: _30.9 cm Mass of the stick from method of torques: Procedure 5 Position of the 100-g mass: 10.0 cm Position of the 200-g mass: _90.0 cm Position of equilibrium of meter stick: Procedure 6 Position of unknown mass...
A fulcrum is placed at the 40 cm mark on a 50 g meter stick (center of mass at the 50 cm mark). A 35 g mass is placed at the 10 cm mark. What mass would have to be placed at the 75 cm mark to balance the meter stick?
10 20 30 40 50 60 70 80 90 The meterstick shown is 100 cm long. It is free to pivot around its center of gravity (CG), which is at the 50 cm mark. There is a 25.0 N block hanging from the 80 cm mark. Decide where each of the other blocks should be placed, one at a time, to balance out the 25.0 N block. 3 2 1 At what mark on the meter stick would you place...
A uniform meter stick (a ruler 100 cm long) is supported by a fulcrum at its 20 cm mark balances when a 200 g mass is suspended at the 0 cm end. Assume that the center of mass of the meter stick is exactly at its middle, the 50 cm mark. Determine the mass of the meter stick, in grams. Please show your work.
2. A meter stick was pivoted at the 30 cm mark with its center of gravity at the 50 cm mark. If a mass of 25.29 g is hanging at the 70.35 cm mark, what mass must be hung from the 11.98 cm mark in order for the system to be in equilibrium? (Take the mass of the stick to be 98 g)
2. A meter stick was pivoted at the 30 cm mark with its center of gravity at the 50 cm mark. If a mass of 25.29 g is hanging at the 70.35 cm mark, what mass must be hung from the 11.98 cm mark in order for the system to be in equilibrium? (Take the mass of the stick to be 98 8)
0/30 Torque and Conditions for Equilibrium. The pivot point of a meter stick is at 50.0 cm. The first mass of 35.0 kg is placed at the 23.0 cm mark of the meterstick. What is the location of a mass - 65.0 kg that balances the meter stick (Sum of torques
the fulcrum is positioned at the 50cm mark on the meter stick. A 50g mass is hung from 67 m mark on the stick. Also a 200g mass is suspended from the 89 cm mark. A. Calculate the total clockwise torque due to these masses B. assuming that the total counterclockwise torque is equal to the answer in (A) above, calculate the position on the meter stick where 315g mass must be suspended in order to balance the stick.