Hydrogen sulfide decomposes according to the following equation,
for which Kc = 0.0000728 at a given temperature. |
First construct the ICE table and then substitute the values and find out the equilibrium concentration values and calculate them as the following
Hydrogen sulfide decomposes according to the following equation, for which Kc = 0.0000728 at a given...
Hydrogen sulfide decomposes according to the following reaction, for which Kc = 9.30 × 10−8 at 700°C: 2 H2S(g) ⇌ 2 H2(g) + S2(g) If 0.55 mol of H2S is placed in a 3.0−L container, what is the equilibrium concentration of H2(g) at 70 degrees Celcius?
Enter your answer in the provided box. Hydrogen sulfide decomposes according to the following reaction, for which Kc = 9.30 × 10−8 at 700°C: 2 H2S(g) ⇌ 2 H2(g) + S2(g) If 0.35 mol of H2S is placed in a 3.0−L container, what is the equilibrium concentration of H2(g) at 700°C?
Enter your answer in the provided box. Hydrogen sulfide decomposes according to the following reaction, for which Kc = 9.30 × 10−8 at 700°C: 2 H2S(g) ⇌ 2 H2(g) + S2(g) If 0.43 mol of H2S is placed in a 3.0−L container, what is the equilibrium concentration of H2(g) at 700°C?
Hydrogen sulfide decomposes according to the following reaction, for which Kc=9.30x10^-8 at 700 degrees C: 2 H2S(g)<-------> 2 H2(g) + S2(g) If 0.57 mol of H2S is placed in 3.0-L container, what is the equlilibrium concentration of H2(g) at 700 degrees C? _______ M
Hydrogen sulfide decomposes according to the following reaction, for which Kc = 9,30 x 10^-8 at 700 degree C.2 H2S(g)leftrightharpoons 2H2(g) + S2(g)It 0.42 mol H2S is placed in a 2.8 L container, what is the equilibrium concentration of H2(g) at 700 degree C? M
Enter your answer in the provided box. Hydrogen sulfide decomposes according to the following reaction, for which Kc = 9.30 × 10^−8 at 700°C: 2 H2S(g) ⇌ 2 H2(g) + S2(g) If 0.41 mol of H2S is placed in a 3.0L container, what is the equilibrium concentration of H2(g) at 700°C?
Enter your answer in the provided box. Hydrogen sulfide decomposes according to the following reaction, for which K.-9.30 x 10-8 at 700°C: 2 H,S(g) = 2 H2(g) +S2() If 0.41 mol of H2S is placed in a 3.0-L container, what is the equilibrium concentration of H2(g) at 700°C?
Hydrogen sulfide decomposes according to the following reaction, for whichKc = 9.30 × 10−8 at 700°C: 2 H2S(g) ⇌ 2 H2(g) + S2(g) If 0.27 mol of H2S is placed in a 3.0−L container, what is the equilibrium concentration of H2(g) at 700°C? ____M
Hydrogen sulfide decomposes according to the following reaction, and at 700.0 °C the value of Kc is 9.30 x 10-8 . 2 H2S (g) ↔ 2 H2 (g) + S2 (g) If a 15.0 L container originally contains 2.10 mol of each product and 0.150 mol of the reactant determine the following. a) Write the expression for Kc. b) Find the value of the reaction quotient, Q. Final Answer for b): c) To which side will the reaction proceed? Circle...
Saved 1 attempts left Check my work Enter your answer in the provided box. Hydrogen sulfide decomposes according to the following reaction, for which K. = 9.30 x 10-8 at 700°C: 2 H2S(g) = 2 H2(g) + S2(9) If 0.49 mol of H2S is placed in a 3.0-L container, what is the equilibrium concentration of Hz() at 700° C? 0.0056 M