sampling test revealed that the BOD5 of a polluted water body at 24C, is at 180mg/l....
sampling test revealed that the BOD5 of a polluted water body at 24C, is at 180mg/l. the ultimate BOD was determined to be 270 mg/L. a) what is the rate constant? b) how will the rate constant change for a temp of 10 degree C?
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sampling test
revealed that the BOD5 of a polluted water body at 24C, is at
180mg/l....
You have collected water samples of the influent (raw sewage) and effluent (treated sewage) at Houston Wastewater Treatment Plant. You plan to conduct the BOD5 test to determine the BOD rate constant,...
You have collected water samples of the influent (raw sewage) and effluent (treated sewage) at Houston Wastewater Treatment Plant. You plan to conduct the BOD5 test to determine the BOD rate constant, k. A. Would you expect the rate constants to be the same or different in these two samples? If different, which would be higher and why? B. If the BOD5 for the raw sewage sample is 600 mg/L, and the ultimate BOD is 650 mg/L at 20oC, find...
(20)1. A wastewater has a BOD5 of 192 mg/L, a reaction rate k of 0.12/day, and...
(20)1. A wastewater has a BOD5 of 192 mg/L, a reaction rate k of 0.12/day, and a total Kjeldahl nitrogen content (TKN) of 35 mg/L. (a) (b) Find the ultimate carbonaceous oxygen demand (CBOD). Find the ultimate nitrogenous oxygen demand (NBOD). Find the total ultimate (or theoretical) oxygen demand (TBOD). Find the remaining BOD (nitrogenous plus carbonaceous) after five days have elapsed.
Two samples are brought to the laboratory for the BOD test. Please calculate BOD5 for both,...
Two samples are brought to the laboratory for the BOD test. Please calculate BOD5 for both, using laboratory DO data. a. For sample A, seeded BOD test was performed. The initial DO concentration in the BOD bottle, which was filled with 2 mL of sample and 298 mL of seeded dilution water, was 8.9 mg/L just after preparation. After an incubation period of five days, the final DO concentration was reported as 1.8 mg/L. Meanwhile, DO concentration in the seed...
Q2. A BOD3 test was run and the results were: Dilution = 20 Initial DO =...
Q2. A BOD3 test was run and the results were: Dilution = 20 Initial DO = 10.6 mg/L Final DO = 2.9 mg/L The reaction rate constant k has been found to be 0.25 day?. (a) What is the BOD3? (2 marks) (b) What would be the ultimate carbonaceous BOD? (3 marks) (c) What is the BOD5? (3 marks) (d) What uld be the remaining oxygen demand after five days (2 marks)
O The town of Gangnam in Seoul, Korea discharges 17360 m3/day of treated wastewater in the Han River. The treated w...
O The town of Gangnam in Seoul, Korea discharges 17360 m3/day of treated wastewater in the Han River. The treated wastewater has a BOD5 of 12 mg/L and a BOD decay constant, k, of 0.12 day at 20 °C. The river has a flow rate of 0.43 m/s and an ultimate BOD, Lo, of 5 mg/L. The DO of the river is 6.5 mg/L and the D0 of the wastewater is 1.0 mg/L (a) Calculate the ultimate BOD of the...
T College of Engineering I0 Ouestion 2 reaction rate constant at 20 "C was determined to be 0.27 ...
t College of Engineering I0 Ouestion 2 reaction rate constant at 20 "C was determined to be 0.27 (a) Determine the BOD exerted in the water after 5 days at 20-C (10%) (b) The temperature of the paper mill emuert is 23°C, 0 057 m's of wastewater which has an ultimate B0D of 720 mg/l. The What is the actual BODs being discharged to the stream ( 10%)? (c) If the paper mill effluent is discharged into a stream having...
QUESTION 1 6 point City of Hope's Wastewater has a ultimate carbonaceous BOD of 300 mg/L...
QUESTION 1 6 point City of Hope's Wastewater has a ultimate carbonaceous BOD of 300 mg/L at 20 oC. The reaction rate k at that temperature has been determined to be 0.2/day. a) Find the BOD5. b)Find the reaction rate coefficient at 15 oC. c) Find BOD5 at 15 oC. O 132 mg/L, 0.18/day, 265 mg/L O 190 mg/L, 0.16/day, 165 mg/L O90 mg/L, 0.16/day, 245 mg/L O 232 mg/L, 0.18/day, 365 mg/L
1. Some pond water contains 20.O mg/L of some algae, which can be represented by the chemical for...
1. Some pond water contains 20.O mg/L of some algae, which can be represented by the chemical formula CsHisO&N. Using the following reactions: CoHisO&N606CO2 6H2ONHa NHs 202 NOs H2O (a) Find the theoretical carbonaceous oxygen demand CBOD (b) Find the nitrogenous oxygen demand NBOD (c) Find the total theoretical biochemical oxygen demand BOD 2. A sandy soil has a hydraulic conductivity of 6.1 x104 m/d, a hydraulic gradient of 0.00141, and porosity of 20%. (a)what is the Darcy velocity (b)what...
Seawater+Wastewater mixing (Water pollution)
Example 7.15: According to the following information, determine whether a fish, which requires 6 \(\mathrm{mg} / \mathrm{L}\) dissolved oxygen, would survive in the river.Given:Waste water flow rate \(\left(\mathrm{Q}_{w}\right)=1.2 \mathrm{~m}^{3} / \mathrm{s}\)River flow rate \(\left(\mathrm{Q}_{r}\right)=10 \mathrm{~m}^{3} / \mathrm{s}\)River temperature \(\left(T_{r}\right)=15^{\circ} \mathrm{C}\)River ultimate \(\mathrm{BOD}\left(\mathrm{BOD}_{r}\right)=2.3 \mathrm{mg} / 1\)River reaeration rate \(=0.4\) per day for BOD testBOD concentration was initially \(9 \mathrm{mg} / \mathrm{l}\), after 5 days was \(6 \mathrm{mg} / 1\) and after an indefinitely long period of time was \(2.5 \mathrm{mg} /...
2. A 5-day BOD of a sample was determined to be 250.0 mg/L and the rate...
2. A 5-day BOD of a sample was determined to be 250.0 mg/L and the rate constant is 0.35 d. What is the ultimate BOD of the sample?
(20)1. A wastewater has a BOD5 of 192 mg/L, a reaction rate k of 0.12/day, and a total Kjeldahl nitrogen content (TKN) of 35 mg/L. (a) (b) Find the ultimate carbonaceous oxygen demand (CBOD). Find the ultimate nitrogenous oxygen demand (NBOD). Find the total ultimate (or theoretical) oxygen demand (TBOD). Find the remaining BOD (nitrogenous plus carbonaceous) after five days have elapsed.
Q2. A BOD3 test was run and the results were: Dilution = 20 Initial DO = 10.6 mg/L Final DO = 2.9 mg/L The reaction rate constant k has been found to be 0.25 day?. (a) What is the BOD3? (2 marks) (b) What would be the ultimate carbonaceous BOD? (3 marks) (c) What is the BOD5? (3 marks) (d) What uld be the remaining oxygen demand after five days (2 marks)
O The town of Gangnam in Seoul, Korea discharges 17360 m3/day of treated wastewater in the Han River. The treated wastewater has a BOD5 of 12 mg/L and a BOD decay constant, k, of 0.12 day at 20 °C. The river has a flow rate of 0.43 m/s and an ultimate BOD, Lo, of 5 mg/L. The DO of the river is 6.5 mg/L and the D0 of the wastewater is 1.0 mg/L (a) Calculate the ultimate BOD of the...
t College of Engineering I0 Ouestion 2 reaction rate constant at 20 "C was determined to be 0.27 (a) Determine the BOD exerted in the water after 5 days at 20-C (10%) (b) The temperature of the paper mill emuert is 23°C, 0 057 m's of wastewater which has an ultimate B0D of 720 mg/l. The What is the actual BODs being discharged to the stream ( 10%)? (c) If the paper mill effluent is discharged into a stream having...
QUESTION 1 6 point City of Hope's Wastewater has a ultimate carbonaceous BOD of 300 mg/L at 20 oC. The reaction rate k at that temperature has been determined to be 0.2/day. a) Find the BOD5. b)Find the reaction rate coefficient at 15 oC. c) Find BOD5 at 15 oC. O 132 mg/L, 0.18/day, 265 mg/L O 190 mg/L, 0.16/day, 165 mg/L O90 mg/L, 0.16/day, 245 mg/L O 232 mg/L, 0.18/day, 365 mg/L
1. Some pond water contains 20.O mg/L of some algae, which can be represented by the chemical formula CsHisO&N. Using the following reactions: CoHisO&N606CO2 6H2ONHa NHs 202 NOs H2O (a) Find the theoretical carbonaceous oxygen demand CBOD (b) Find the nitrogenous oxygen demand NBOD (c) Find the total theoretical biochemical oxygen demand BOD 2. A sandy soil has a hydraulic conductivity of 6.1 x104 m/d, a hydraulic gradient of 0.00141, and porosity of 20%. (a)what is the Darcy velocity (b)what...
2. A 5-day BOD of a sample was determined to be 250.0 mg/L and the rate constant is 0.35 d. What is the ultimate BOD of the sample?
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