Assume that females have pulse rates that are normally distributed with a mean of
mu equals 72.0μ=72.0
beats per minute and a standard deviation of
sigma equals 12.5σ=12.5
beats per minute. Complete parts (a) through (c) below.
a. If 1 adult female is randomly selected, find the probability that her pulse rate is less than 78 beats per minute.
b. If 25 adult females are randomly selected, find the probability that they have pulse rates with a mean less than 78
beats per minute.
Please don't hesitate to give a "thumbs up" in case you're satisfied with the answer
a. P(X<78) = P(Z< (78-72)/12.5) = P(Z< 0.48) = .6844
So, p(that her pulse rate is lower than 78bpm) = .6844
b. P(Xbar < 78) = P(Z< (78-72)/(12.5/sqrt(25)) = P(Z< 2.4) = .9918
Assume that females have pulse rates that are normally distributed with a mean of mu equals...
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