Suppose that X is a binomial random variable with
n = 11 and p = 0.28 . Find P( 5 ).
Write only a number as your answer. Round to 4 decimal places (for
example 0.1849). Do not write as a percentage.
Solution
Given that ,
p = 0.28
1 - p = 1 - 0.28 = 0.72
n = 11
x = 5
Using binomial probability formula ,
P(X = x) = ((n! / x! (n - x)!) * px * (1 - p)n - x
P(X = 5) = ((11! / 5! (11 - 5)!) * 0.285 * (0.72)11 - 5
= ((11! / 5! (6)!) * 0.285 * (0.72)6
= 0.1108
P(5) = 0.1108
Suppose that X is a binomial random variable with n = 11 and p = 0.28...
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