Question

How can I find a p-value when given a test statistic only with no df? I...

How can I find a p-value when given a test statistic only with no df? I am preferably looking for a method with a TI-84 but will accept any answer, here is the question I am trying to answer:

Use the given information to find the P-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). The test statistic in a left-tailed test is z = -2.05.

a- 0.0202; reject the null hypothesis

B-0.0453 fail to reject the null hypothesis

C-0.4798; fail to reject the null hypothesis

D= 0.0404; reject the null hypothesis

THANKS!

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Solution :

P-value = P(z < -2.05) = 0.0202

P-value < 0.05

a- 0.0202; reject the null hypothesis

Add a comment
Know the answer?
Add Answer to:
How can I find a p-value when given a test statistic only with no df? I...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • The P-value for a hypothesis test is shown. Use the P-value to decide whether to reject...

    The P-value for a hypothesis test is shown. Use the P-value to decide whether to reject H when the level of significance is (a) a= 0.01, (b) a 0.05, and (c) a0.10. P 0.0749 (a) Do you reject or fail to reject Ho at the 0.01 level of significance? O A. Reject H because the P-value, 0.0749, is greater than a=0.01 O B. Fail to reject Ho because the P-value, 0.0749, is less than a = 0.01 O C. Reject...

  • Use the given information to find the p-value. Use a 0.05 significance level and state the...

    Use the given information to find the p-value. Use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). a. The test statistic in a right-tailed test is z = 1.00. b. The test statistic in a test with alternative hypothesis p 6= 5/7 is z = 2.05. c. The test statistic in a test with alternative hypothesis p < 2/3 in z = −0.45.

  • Find the critical value for the indicated hypothesis test, then use this value and the provided...

    Find the critical value for the indicated hypothesis test, then use this value and the provided information to make a conclusion about the null hypothesis (i.e., reject or fail to reject the null hypothesis). 1.The test statistic in a left-tailed test is z = −2.05; significance level α = 8% 2. Test at the significance level α = 5% the hypothesis H0: p ≤ 0.04, given that the test statistic is z = 1.82. 3. Test at the significance level...

  • Find the P value for the indicated hypothesis test with the given standardized test statistic z...

    Find the P value for the indicated hypothesis test with the given standardized test statistic z Decide whether to reject Ho for the given level of significance ? Right-tailed test with test statistic z-1.55 and ?-0.04 P-value(Round to four decimal places as needed.) State your conclusion O Reject Ho O Fail to reject Ho

  • Find the P-value for the indicated hypothesis test with the given standardized test statistic, z. Decide...

    Find the P-value for the indicated hypothesis test with the given standardized test statistic, z. Decide whether to reject Ho for the given level of significance a Right-tailed test with test statistic z = 1.32 and a = 0.03 P-value = (Round to four decimal places as needed.) State your conclusion O Reject Ho Fail to reject Ho

  • Find the P-value for the indicated hypothesis test with the given standardized test statistic, z. Decide...

    Find the P-value for the indicated hypothesis test with the given standardized test statistic, z. Decide whether to reject Hy for the given level of significance a. Two-tailed test with test statistic zs - 2.26 and 0.03 P-value = (Round to four decimal places as needed.) State your conclusion O Fail to reject Ho Reject Ho O

  • 1. Find the​ P-value for the indicated hypothesis test with the given standardized test​ statistic, z....

    1. Find the​ P-value for the indicated hypothesis test with the given standardized test​ statistic, z. Decide whether to reject Upper H 0 for the given level of significance alpha. ​Two-tailed test with test statistic z= -1.95 and alpha=0.04 ​ P-value= ? ​(Round to four decimal places as​ needed.) Reject H0 or fail to reject? 2. Find the critical​ value(s) for a​ left-tailed z-test with alpha=0.01. Include a graph with your answer. The critical​ value(s) is(are) ___ ​(Round to two...

  • The test statistic in a two dash tailed test is z= -2.84. Determine the​ P-value and...

    The test statistic in a two dash tailed test is z= -2.84. Determine the​ P-value and decide​ whether, at the 1​% significance​ level, the data provide sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis. *Please show me a way to do it on the calculator (ti-84)*

  • Provide an appropriate response. Find the P-value for the hypothesis test with the standardized test statistic...

    Provide an appropriate response. Find the P-value for the hypothesis test with the standardized test statistic z. Decide whether to reject H o for the level of significance a. Two-tailed test z= 1.95 a = 0.05 0.0512; fail to reject Ho 0.0256; reject Ho 0.9744; fail to reject Ho 0.0512; reject Ho QUESTIO 8 points Save Answer Provide an appropriate response. Find the P-value for the hypothesis test with the standardized test statistic z. Decide whether to reject H o...

  • I spefically need to see how the test statistic and critical value is calculated. Test the...

    I spefically need to see how the test statistic and critical value is calculated. Test the claim that the proportion of men who own cats is significantly different than 80% at the 0.02 significance level. The null and alternative hypothesis would be: The test is: left-tailed right-tailed two-tailed Based on a sample of 55 people, 78% owned cats The test statistic is: (to 2 decimals) The positive critical value is: (to 2 decimals) Based on this we: Reject the null...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT