How can I find a p-value when given a test statistic only with no df? I am preferably looking for a method with a TI-84 but will accept any answer, here is the question I am trying to answer:
Use the given information to find the P-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). The test statistic in a left-tailed test is z = -2.05.
a- 0.0202; reject the null hypothesis
B-0.0453 fail to reject the null hypothesis
C-0.4798; fail to reject the null hypothesis
D= 0.0404; reject the null hypothesis
THANKS!
Solution :
P-value = P(z < -2.05) = 0.0202
P-value < 0.05
a- 0.0202; reject the null hypothesis
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