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During glycogen degradation glucose-1-phosphate is converted to glucose-6-phosphate and is an example of a coupled reaction....

During glycogen degradation glucose-1-phosphate is converted to glucose-6-phosphate and is an example of a coupled reaction. If the phosphoryl group transfer potential for glucose-1-phosphate is -20.9 kJ/mol and for glucose-6-phosphate is -13.8 kJ/mol, then what is the Keq (K) at 298 K? Is the conversion of glucose-1-phosphate to glucose-6-phosphate favorable or unfavorable under standard conditions?

ΔG° = -RT ln K where R = 8.315 x 10-3 kJ/mol*K

K = 0.057 and the reaction is unfavorable.
K = 17.5 and the reaction is favorable.
K = 0.057 and the reaction is favorable.
K = 17.5 and the reaction is unfavorable.
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Answer #1

Answer:

To decide favourable or unfavourable

Here in biological transformation,

The value of equilibrium constant for the reaction is given as follows

i.e.,

- K = 17.5 & the reaction is favourable

So The reaction has a value

Thus the reaction is spontaneous or favourable.

So option B is correct

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