Imagine a population that has 179 A1A1 individuals, 184 A1A2 individuals, and 26 A2A2 individuals. Male...
Imagine a population that has 179 A1A1 individuals, 184 A1A2 individuals, and 26 A2A2 individuals. Male A1A1 is the preferred mate of females and gets all the matings. What would the genotype frequencies be for the A1A2 offspring of this population?
Homework Answers
Answer:
Each individual has two alleles.
179A1A1 = 179*2 = 358 A1 alleles
184 A1A2 = A1 184 & A2 184 alleles
26 A2A2 = 52 A2 alleles
Total alleles = 778
Total A1 alleles = 358 + 184 = 542
Frequency of A1 allele = 542/778 = 0.697
Total A2 alleles = 52 + 184 = 236
Frequency of A2 allele = 236/778 = 0.303
Frequency of A1A2 genotype = 2A1A2 = 2 * 0.697 * 0.303 = 0.422 or 42%
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