Assortative mating: Assortative mating is a nonrandom mating pattern where individuals with similar genotypes and/or phenotypes...
Assortative mating: Assortative mating is a
nonrandom mating pattern where individuals with similar genotypes
and/or phenotypes mate with one another more frequently than what
would be expected under a random mating pattern. Researchers
studying this topic collected data on eye colors of 205
Scandinavian men and their female partners. The table below
summarizes the results (rows represent male eye color while columns
represent female eye color). For simplicity, we only include
heterosexual relationships in this exercise.
(please round any numerical answers to 4 decimal
places)
| Blue | Brown | Green | Total | |
|---|---|---|---|---|
| Blue | 43 | 29 | 30 | 102 |
| Brown | 13 | 22 | 19 | 54 |
| Green | 15 | 7 | 27 | 49 |
| Total | 71 | 58 | 76 | 205 |
a) What is the probability that a randomly chosen male respondent
or his partner has blue eyes?
b) What is the probability that a randomly chosen male respondent
with blue eyes has a partner with blue eyes?
c) What is the probability that a randomly chosen male respondent
with brown eyes has a partner with blue eyes?
d) What is the probability of a randomly chosen male respondent
with green eyes having a partner with blue eyes?
e) Does it appear that the eye colors of male respondents and their
partners are independent? Explain.
- No, it is much more likely for a male with blue eyes to have a blue-eyed partner than it is for a male with any other eye color
- Yes, people don't choose spouses based on eye color
Homework Answers
Add Answer to:
Assortative mating: Assortative mating is a
nonrandom mating pattern where individuals with similar genotypes
and/or phenotypes...
Uw intro/Instructions Assortative Mating: Assortative mating is a nonrandom mating pattern where individuals with similar genotypes...
Uw intro/Instructions Assortative Mating: Assortative mating is a nonrandom mating pattern where individuals with similar genotypes and/or phenotypes mate with one another more frequently than what would be expected under a random mating pattern Researchers studying this topic collected data on eye colors of 190 Scandinavian men and their female partners. The table below summarizes the results (rows represent male eye color while columns represent female eye color) For simplicity, we only include heterosexual relationships in this exercise. (Round any...
genetics problem: 5. On a small island, 235 mating individuals are all homozygous for brown eyes....
genetics problem:
5. On a small island, 235 mating individuals are all homozygous for brown eyes. An epidemic wipes out all but 10 young women, 2 young men, and two elderly women (both >70 years old). A boatload of foreigners arrives; the foreign population consists of six heterozygous brown-eyed young women, four homozygous brown-eyed young men, and 10 blue-eyed young men. Assuming that eye color is controlled by a single locus with the brown allele being dominant (blatantly incorrect, but...
Eye Color\Gender Females Males TOTAL Brown 20 5 25 Blue 15 30 45 Green 30 50...
Eye Color\Gender Females Males TOTAL Brown 20 5 25 Blue 15 30 45 Green 30 50 80 TOTAL 65 85 150 1. What is the probability of selecting an individual has brown eyes or is a female? 2. What is the probability of selecting an individual with brown eyes given that they are male? 3. What is the probability of selecting an individual is a female? 4. What is the probability of selecting an individual is a female with brown...
tree n elor Grandpa Grandma Dad Shannon (mom) Joseph Annabel Brown eyed male Green eyed male...
tree n elor Grandpa Grandma Dad Shannon (mom) Joseph Annabel Brown eyed male Green eyed male Grandpa Brownieved female Green eyed fernale color blind female Dad Normal female och blind male Nommal male Joseph is grandma is color blind his grandpa and mum are not shat color blind but Joseph and his dad are PUNNETT SQUARE INTERACTIVE Grandma Shannon (Mom) xn Xc Xnx Grandpa SUBMIT Construct the Punnet more info. HOME THEORY MEDIA MISSION Use the following abbreviations: Xc: X...
3)Assume that green eyes in humans are dominant to blue eyes. Further assume that these are the o...
3)Assume that green eyes in humans are dominant to blue eyes. Further assume that these are the only two colors and that human eye color follows Mendel’s rules. A true-breeding greeneyed male produces offspring with a true-breeding blue-eyed female. What color eyes will the offspring have?
For the purpose of this problem assume that in humans eye color is controlled by a...
For the purpose of this problem assume that in humans eye color is controlled by a single gene and that the allele for brown eyes is dominant to the blue-eye allele. Two brown-eyed parents planning a pregnancy already have a blue-eyed daughter. PLEASE NOTE: gender (being male or female) is a SECOND trait (like a second Punnett square), but no need for a Punnett square because the chance that an offspring will be male or female is always 1/2. Assign...
Uption 4. The inheritance of hair and eye color is very complicated. Scientists have found approximately...
Uption 4. The inheritance of hair and eye color is very complicated. Scientists have found approximately 10-20 genes responsible for determining hair and eye color in humans (sheesh - I thought a dihybrid cross with 2 genes was bad...). Although many genes are involved in producing these phenotypes, it does seem that just a few genes play a major role in determining the color of our hair and eyes. The following is a simplified, but still somewhat realistic view of...
Question 4 (1 point) Continue Consider a mating between a single F2 male that is phenotypically...
Question 4 (1 point) Continue Consider a mating between a single F2 male that is phenotypically wild-type (i.e., red eyes and tan body) and a single, phenotypically wild-type F2 female. What is the probability that ALL of the resulting F3 progeny will be true breeding and have red eyes and tan bodies? 1/6 01/12 1/256 1/36 1/8 1/64 1/18 1/32 Question 3 (1 point) Saved In flies (Drosophila), loss of function mutations in the X-linked white gene cause a recessive...
Question 131 pts If the alleles for different traits (eye and hair color) are on different...
Question 131 pts If the alleles for different traits (eye and hair color) are on different chromosomes, then during anaphase of meiosis I and II, the chromosomes or eye and hair color can end up in different gametes. This is called _________________. Group of answer choices linked traits incomplete dominance independent assortment complete dominance Question 141 pts In a dihybrid cross for brown/blue eyes and big/little teeth, what is the probability of having a big tooth, brown eyed child? Group...
Need 5-9 and number 11 all answered. Thx 5. How can two individuals with brown eyes(B)...
Need 5-9 and number 11 all answered. Thx
5. How can two individuals with brown eyes(B) have a blue (b) eyed baby? Show the genotypes of the parents and Punnett square to prove your answer. What are the chances of a blue-eyed baby? 6. A homozygous tongue roller (T) is married to a non-tongue roller(t). If they have 5 children, how many of them will be tongue rollers? Use Punnett square to support and explain your answer. 7. Let's imagine...
Uw intro/Instructions Assortative Mating: Assortative mating is a nonrandom mating pattern where individuals with similar genotypes and/or phenotypes mate with one another more frequently than what would be expected under a random mating pattern Researchers studying this topic collected data on eye colors of 190 Scandinavian men and their female partners. The table below summarizes the results (rows represent male eye color while columns represent female eye color) For simplicity, we only include heterosexual relationships in this exercise. (Round any...
genetics problem:
5. On a small island, 235 mating individuals are all homozygous for brown eyes. An epidemic wipes out all but 10 young women, 2 young men, and two elderly women (both >70 years old). A boatload of foreigners arrives; the foreign population consists of six heterozygous brown-eyed young women, four homozygous brown-eyed young men, and 10 blue-eyed young men. Assuming that eye color is controlled by a single locus with the brown allele being dominant (blatantly incorrect, but...
Eye Color\Gender Females Males TOTAL Brown 20 5 25 Blue 15 30 45 Green 30 50 80 TOTAL 65 85 150 1. What is the probability of selecting an individual has brown eyes or is a female? 2. What is the probability of selecting an individual with brown eyes given that they are male? 3. What is the probability of selecting an individual is a female? 4. What is the probability of selecting an individual is a female with brown...
tree n elor Grandpa Grandma Dad Shannon (mom) Joseph Annabel Brown eyed male Green eyed male Grandpa Brownieved female Green eyed fernale color blind female Dad Normal female och blind male Nommal male Joseph is grandma is color blind his grandpa and mum are not shat color blind but Joseph and his dad are PUNNETT SQUARE INTERACTIVE Grandma Shannon (Mom) xn Xc Xnx Grandpa SUBMIT Construct the Punnet more info. HOME THEORY MEDIA MISSION Use the following abbreviations: Xc: X...
For the purpose of this problem assume that in humans eye color is controlled by a single gene and that the allele for brown eyes is dominant to the blue-eye allele. Two brown-eyed parents planning a pregnancy already have a blue-eyed daughter. PLEASE NOTE: gender (being male or female) is a SECOND trait (like a second Punnett square), but no need for a Punnett square because the chance that an offspring will be male or female is always 1/2. Assign...
Uption 4. The inheritance of hair and eye color is very complicated. Scientists have found approximately 10-20 genes responsible for determining hair and eye color in humans (sheesh - I thought a dihybrid cross with 2 genes was bad...). Although many genes are involved in producing these phenotypes, it does seem that just a few genes play a major role in determining the color of our hair and eyes. The following is a simplified, but still somewhat realistic view of...
Question 4 (1 point) Continue Consider a mating between a single F2 male that is phenotypically wild-type (i.e., red eyes and tan body) and a single, phenotypically wild-type F2 female. What is the probability that ALL of the resulting F3 progeny will be true breeding and have red eyes and tan bodies? 1/6 01/12 1/256 1/36 1/8 1/64 1/18 1/32 Question 3 (1 point) Saved In flies (Drosophila), loss of function mutations in the X-linked white gene cause a recessive...
Need 5-9 and number 11 all answered. Thx
5. How can two individuals with brown eyes(B) have a blue (b) eyed baby? Show the genotypes of the parents and Punnett square to prove your answer. What are the chances of a blue-eyed baby? 6. A homozygous tongue roller (T) is married to a non-tongue roller(t). If they have 5 children, how many of them will be tongue rollers? Use Punnett square to support and explain your answer. 7. Let's imagine...
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