For a normal distribution with mean of 70 and sd 10, what is the minimum score...
For a normal distribution with mean of 70 and sd 10, what is the minimum score necessary to be in the top 60% of the distribution?
Homework Answers
solution:-
given that mean = 70 , standard deviation = 10
The top 60 % represents 0.60 probability in tail. First, find the corresponding z-score for 0.60 in tail: z = 0.25
X-score: = X = µ + z* σ
x = 70 + 0.25 * 10
x = 72.5
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For a normal distribution with mean of 70 and sd 10, what is the
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what z score value separates the top 70% of a normal distribution from the bottom 30%?
what z score value separates the top 70% of a normal distribution from the bottom 30%?
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