Calculate the length in meters of a simple pendulum that has a period of 3.00s if it is located at sea level where gravity is 9.81 m/s2
L = _______________
Calculate the length in meters of a simple pendulum that has a period of 3.00s if...
The period T of a simple pendulum is given by T=2πLg−−√T=2πLg where L is the length of the pendulum and g is the acceleration due to gravity. Assume that g = 9.80 m/s2 exactly, and that L, in meters, is lognormal with parameters μL = 0.8 and σ2L=0.05.σL2=0.05. NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Find P(T > 3).
(a) What is the length of a simple pendulum that oscillates with a period of 2.6 s on Earth, where the acceleration due to gravity is 9.80 m/s2, and on Mars, where the acceleration due to gravity is 3.70 m/s2? LE = LM = Enter a number. Im (b) What mass would you need to suspend from a spring with a force constant of 20 N/m in order for the mass-spring system to oscillate with a period of 2.6 s...
(a) What is the length of a simple pendulum that oscillates with a period of 3.0 s on Earth, where the acceleration due to gravity is 9.80 m/s2, and on Mars, where the acceleration due to gravity is 3.70 m/s2? LE = Lм %3 m (b) What mass would you need to suspend from a spring with a force constant of 20 N/m in order for the mass-spring system to oscillate with a period of 3.0 s on Earth, where...
A simple pendulum of length 2 meters takes a time of 16 seconds to finish 8 oscillations. The acceleration due to gravity acting on this pendulum is given by A)19.72 m/s2 B)27.4 m/s2 C)9.8 m/s2 D)4.9 m/s2
A simple pendulum has a period of 1.74 s. What is its length? The acceleration due to gravity is 9.8 m/s2 . Answer in units of m.
D Question 12 10 pts A simple pendulum of length 2 meters takes a time of 16 seconds to finish 8 oscillations. The accelerat due to gravity acting on this pendulum is given by 9.8 m/s2 19.72 m/s2 4.9 m/s2 O 27.4m/s2 No new data to save. Last checked at 10:37am Submit Quiz MacBook Air 20. 299..
4) a) Calculate the period of a simple pendulum if the length of the string is g on the moon. gon Moon is 16of g on Earth. gon Earth = 9.8 m/s: 1.5 meter? b) Calculate the period of the simple pendulum if you take to Mars. g on Mars 3.7 m/s What is the ratio of the period of the above simple pendulum to the period of a simple pendulum which is 4 times longer? b) d) What happens...
A certain simple pendulum has a period on earth of 1.72 s. What is its period on the surface of Mars,where the acceleration due to gravity is 3.71 m/s2 ?
The period T of a simple pendulum with small oscillations is calculated from the formula T=2pi sqrt(L/g) where L is the length of the pendulum and g is the acceleration due to gravity. suppose that measured values of L and g have errors and are corrected with new values where L is increased from 4m to 4.5m and g is increased from 9 m/s2 to 9.8 m/s2. Use differentials to estimate the change in the period. Does the period increase...
A pendulum with a length of precisely 0.98 m can be used to measure the acceleration due to gravity, g. Such a device is called a gravimeter.How long do 80 oscillations take at sea level, where g= 9.81 m/s2? Suppose you take a gravimeter to a spot on Venus where the value of g is 0.89% less than the value of g at sea level on Earth. How long do 80 oscillations take at this place on Venus? Would you be able...