A simple pendulum has a period of 1.74 s. What is its length? The acceleration due to gravity is 9.8 m/s2 . Answer in units of m.
the equation for the period of a simple pendulum:
T = 2π√(l/g)
g is the gravitational acceleration
on earth: g = 9.81m/s2, T = 1.74s
l = T2g/(4π2)
l = (1.74s)2 *9.81m/s2 / (4π2)
l = 0.7523 m
A simple pendulum has a period of 1.74 s. What is its length? The acceleration due...
A certain simple pendulum has a period on earth of 1.72 s. What is its period on the surface of Mars,where the acceleration due to gravity is 3.71 m/s2 ?
(a) What is the length of a simple pendulum that oscillates with a period of 2.6 s on Earth, where the acceleration due to gravity is 9.80 m/s2, and on Mars, where the acceleration due to gravity is 3.70 m/s2? LE = LM = Enter a number. Im (b) What mass would you need to suspend from a spring with a force constant of 20 N/m in order for the mass-spring system to oscillate with a period of 2.6 s...
(a) What is the length of a simple pendulum that oscillates with a period of 3.0 s on Earth, where the acceleration due to gravity is 9.80 m/s2, and on Mars, where the acceleration due to gravity is 3.70 m/s2? LE = Lм %3 m (b) What mass would you need to suspend from a spring with a force constant of 20 N/m in order for the mass-spring system to oscillate with a period of 3.0 s on Earth, where...
When a pendulum with a period of 2.00000 s is moved to a new location from one where the acceleration due to gravity was 9.80 m/s2, its new period becomes 1.99900 s. By how much does the acceleration due to gravity differ at its new location? Incorrect: Your answer is incorrect. How is the period of the pendulum related to the length of the pendulum and the acceleration due to gravity at the location of the pendulum? What happens to...
A simple pendulum of length 2 meters takes a time of 16 seconds to finish 8 oscillations. The acceleration due to gravity acting on this pendulum is given by A)19.72 m/s2 B)27.4 m/s2 C)9.8 m/s2 D)4.9 m/s2
The period of a simple pendulum in a grandfather clock on another planet is 1.80 s. What is the acceleration due to gravity on this planet if the length of the pendulum is 1.00 m.
What is the period (in s) of a simple pendulum of length 0.12 m and mass 0.31 kg near the surface of a planet where the gravitational acceleration is 11 m/s2? Enter a number with 2 digits behind the decimal point..
Calculate the length in meters of a simple pendulum that has a period of 3.00s if it is located at sea level where gravity is 9.81 m/s2 L = _______________
6. Explain a Simple Pendulum. Draw a figure of a simple pendulum. Page 5 of 9 A simple pendulum of length 2.5 m was setup in your room. You find that it execute complete oscillation in 100s. a) Calculate the time for 1 oscillation ( Period) b) Find the acceleration due to gravity (g)? c) If the length of the simple pendulum is double (twice of initial value), what is the incr its time period?
13.11 A pendulum has a length of 4.8 m. a) At a location where the acceleration due to gravity is 9.80 m/s, what is the period of the pendulum? b) If the period of a pendulum is twice as much the value found in part a, what is the length?