13.11 A pendulum has a length of 4.8 m. a) At a location where the acceleration...
When a pendulum with a period of 2.00000 s is moved to a new location from one where the acceleration due to gravity was 9.80 m/s2, its new period becomes 1.99900 s. By how much does the acceleration due to gravity differ at its new location? Incorrect: Your answer is incorrect. How is the period of the pendulum related to the length of the pendulum and the acceleration due to gravity at the location of the pendulum? What happens to...
When a pendulum with a period of 2.00000 s in one location (g = 9.80 m/s) is moved to a new location from one where the period is now 1.99844 s. What is the change in acceleration (in m/s2) due to gravity at its new location?
When a pendulum with a period of 2.00000 s in one location (g = 9.80 m/s2) is moved to a new location from one where the period is now 1.99808 s. What is the change in acceleration in m/s) due to gravity at its new location? m/s²
When a pendulum with a period of 2.00000 s in one location (g = 9.80 m/s2) is moved to a new location from one where the period is now 1.99869 s. What is the change in acceleration (in m/s2) due to gravity at its new location?
TUDIEM 14 Geoff counts the number of oscillations of a simple pendulum at a location where the acceleration due to gravity is 9.80 m/s, and finds that it takes 28.0 s for 17 complete cycles. 1) Calculate the length of the pendulum. (Express your answer to three significant figures.) m Submit
(a) What is the length of a simple pendulum that oscillates with a period of 2.6 s on Earth, where the acceleration due to gravity is 9.80 m/s2, and on Mars, where the acceleration due to gravity is 3.70 m/s2? LE = LM = Enter a number. Im (b) What mass would you need to suspend from a spring with a force constant of 20 N/m in order for the mass-spring system to oscillate with a period of 2.6 s...
(a) What is the length of a simple pendulum that oscillates with a period of 3.0 s on Earth, where the acceleration due to gravity is 9.80 m/s2, and on Mars, where the acceleration due to gravity is 3.70 m/s2? LE = Lм %3 m (b) What mass would you need to suspend from a spring with a force constant of 20 N/m in order for the mass-spring system to oscillate with a period of 3.0 s on Earth, where...
A simple pendulum of length 2.5 m was setup in your room. You find that it execute so complete oscillation in 108.5 s. a) Calculate the time for 1 oscillation ( Period) b) Find the acceleration due to gravity (g)? c) If the length of the simple pendulum is double (twice of initial value), what is the increase of its time period?
Consider the pendulum shown at the right. It has the following characteristics: • T = 1.33 s • m=0.251 kg Answer the three questions below, using three significant digits. Part A: What is the value of the angular frequency (w) of the pendulum? T. 4.72 rad/s Part B: What is the length (L) of the pendulum? L = .44 m Part C: How might the period of this pendulum be different if it were moved from Earth to the planet...
A simple pendulum has a period of 1.74 s. What is its length? The acceleration due to gravity is 9.8 m/s2 . Answer in units of m.