Question

When a pendulum with a period of 2.00000 s in one location (g = 9.80 m/s2) is moved to a new location from one where the period is now 1.99808 s. What is the change in acceleration in m/s) due to gravity at its new location? m/s²

Answer 1

Given is :-

Ti = 25,91 = 9.80m/s2

T2 = 1.99808s

now,

we know that the time period in SHM is given by

T = 27

and the ration of time periods is given by

$\frac{T_2}{T_1} = \sqrt{\frac{g_1}{g_2}}$

by plugging all the values we get

1.99808s 9.80m/s2 92 2s

which gives us

92 = 9.81884m/s2

hence,

the change in acceleration due to gravity is

91 - 92 = ܠ

or

Ag = 9.81884m/s2 – 9.80m/s

which gives us

Ag = 0.01884 m/s2