Question

When a pendulum with a period of 2.00000 s is moved to a new location from one where the acceleration due to gravity was 9.80 m/s2, its new period becomes 1.99900 s. By how much does the acceleration due to gravity differ at its new location?
Incorrect: Your answer is incorrect.
How is the period of the pendulum related to the length of the pendulum and the acceleration due to gravity at the location of the pendulum? What happens to the length of the pendulum as it is moved to the new location? m/s2
Additional Materials

please provide steps and work thank you.

Answer 1

For a simple pendulum the period T is proportional to 1/g½

Told/Tnew = (gnew/gold)½.
gnew = gold*(Told/Tnew)
= 9.8*(2/1.99900)^2
= 9.81 m/s^2.

For a simple pendulum the period T is proportional to (L/g)½.
If g increases slightly, you will have to increase the length of the pendulum.