When a pendulum with a period of 2.00000 s in one location (g = 9.80 m/s2)...

Question

Question

When a pendulum with a period of 2.00000 s in one location (g = 9.80 m/s2) is moved to a new location from one where the peri

Answer 1

Answer #1

Solution)

Given,

Time Period, T1=2s

Time Period, T2=1.99869 s

We know,

T1=2pi*(L/g1)

On squaring both sides,

L=T1^2*g1/4pi^2

Also, T2^2= 4pi^2*L/g2

So, L=(T2^2*g2)/4pi^2

Hence, g2=g1(T1/T2)^2

Substitute values,

We have, g2=9.8*(2/1.99869)^2=9.812 m/s^2 (Ans)

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Answer 2

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