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Consider 1.0 L of a solution which is 0.45 M HF and 0.2 M NaF (Ka...

Consider 1.0 L of a solution which is 0.45 M HF and 0.2 M NaF (Ka for HF = 7.2 x 10-4). Assume 2 significant figures in all of the given concentrations so that you should calculate all of the following pH values to two decimal places.

Calculate the pH after 0.10 mol of HCl has been added to the original solution. Assume no volume change on addition of HCl.

Why do we need to convert to Kb?

I know the answer is 2.4 and I am just wondering why you convert to Kb and then go from pOH to pH when there is no OH- present?
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