2. A particle has a constant acceleration of ?⃗ = (6.0
m s
2 ⁄ )?̂ + (4.0 m s
2 ⁄ )?. At ̂ ? = 0, the
velocity is zero and the position vector is ?⃗ 0 = (10 m)?̂.
(a) Find the velocity and position vectors as a function of time
?.
b)Find the equation of the particle’s path in the xy plane and sketch the
path.
Given:
The acceleration of the particle is,
The velocity at time t=0 is,
The position vector of the particle at time t=0 is,
Part (a)
The velocity vector as a function of time is given by,
The position vector of the particle as a function of time is given by,
Part (b)
For the position vector of the particle, we can say that,
Eliminating the t from both equations, we get,
The path on xy plane will be:
2. A particle has a constant acceleration of ?⃗ = (6.0 m s 2 ⁄ )?̂...
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