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In this case, $10 is 0x00000001 and $0 is 0 and the PC is 0x00003014. The...

In this case, $10 is 0x00000001 and $0 is 0 and the PC is 0x00003014.

The line of code is bne $10, $0, 0xfffffffc

I don't know why the PC goes to 0x00003008 after. Please explain this

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Answer #1

PC is program counter that stores the address of the current instruction being executed.

Initial Case:

bne $10, $0, 0xfffffffc

PC is 0x00003014, 10 is 0x00000001 and $0 is 0

Now, since $10 and $0 are not equal, therefore it branches off.

Usually, for any address the next value of PC if ((address_of_current_instruction) + 4) but if this calculation overflows the top of the address space, the result is UNPREDICTABLE.

In other words, programs should not rely on sequential execution of the instruction at address 0x00000000 after the instruction at address 0xFFFFFFFC.

Therefore, when it branches of to 0xFFFFFFFC, the PC value becomes unpredictable and hence you're getting a value: 0x00003008 which is unpredictable.

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