Question

Suppose there is an urn containing 5 red, 4 white, and 11 blue balls. We drawn six balls from the urn (no replacement)

(a) Find the number of ways (not the probability) of choosing a red ball, then a blue ball, then exactly 2 white balls, and finally exactly 2 blue balls.

(b)Find the number of ways of choosing 2 red balls initially , then at least 3 blue balls, then a green ball.

(c) Find the number of ways of choosing 2 red balls initially and then at least 2 blue balls of the remaining 4 drawn.

(d) Find the number of ways of choosing at least 2 red balls amongst the 6 chosen?

Answer 1