Prove each case f(n) = O(g(n)) by providing enough justification. 1) f(n) = n2.5 2) f(n)...
Prove each case f(n) = O(g(n)) by providing enough justification.
1) f(n) = n2.5
2) f(n) = n10
Homework Answers
Big-Oh definition: ------------------- f(n) = O(g(n)) means there are positive constants c and k, such that 0 ≤ f(n) ≤ cg(n) for all n ≥ k. 1) f(n) = n2.5 0 <= f(n) <= 2n^2.5 Where c=2, n>0 and g(n)=n^2.5 So, from the definition of Big-Oh we can say that f(n)=2) f(n) = n10 0 <= f(n) <= 2n^10 Where c=2, n>0 and g(n)=n^10 So, from the definition of Big-Oh we can say that f(n)=
2) f(n) = n10
0 <= f(n) <= 2n^10
Where c=2, n>0 and g(n)=n^10
So, from the definition of Big-Oh we can say that f(n)=
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Prove each case f(n) = O(g(n)) by providing enough
justification.
1) f(n) = n2.5
2) f(n)...
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