The average fuel efficiency of vehicles in a light weight class in 2012 was 31mpg. If...
The average fuel efficiency of vehicles in a light weight class in 2012 was 31mpg. If the standard deviation of the population (σ) was 3 and the gas ratings were normally distributed, what is the probability that the mean mpg for a randomly selected light weight vehicle is between 27mpg and 34mpg?
Homework Answers
Solution :
Given that ,
mean = 
= 31
standard deviation = 
= 3
P(27< x <34 ) = P[(27-31) /3 < (x - 
) / < (34-31) /3 )]
= P( -1.33< Z < 1)
= P(Z <1 ) - P(Z < -1.33)
Using z table
= 0.8413 - 0.0918
probability= 0.7495
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