Question

On the off chance that you have a 6:30 weakening component, and you utilize 6 mL...

On the off chance that you have a 6:30 weakening component, and you utilize 6 mL of stock you will require 24 mL of water to make up _________ mL of aggregate of volume. Utilizing a similar proportion, in the event that you utilize 1 mL of stock, you will require ________ mL of water to make up _________ mL of all out volume.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Case 1:
Aggregate volume = volume of stock + volume of water
= 6 + 24
= 30 mL

Case 2:
Volume of stock is 1 mL
We are decreasing volume of stock in case 1 by a factor of 6

So,
Volume of water = volume of water in case 1 / 6
= 24 mL / 6
= 4 mL

Aggregate volume = Aggregate volume in case 1 / 6
= 30 mL / 6
= 5 mL

Answer:
30, 4, 5

Add a comment
Know the answer?
Add Answer to:
On the off chance that you have a 6:30 weakening component, and you utilize 6 mL...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • You have a stock solution that contains 24 mg/ml of protein. You want to make a...

    You have a stock solution that contains 24 mg/ml of protein. You want to make a set of standards with the following concentrations: 12 mg/ml, 6 mg/ml, 3 mg/ml and 1.5 mg/ml.               You need a minimum of 500 ul of each standard after all dilutions are completed. Using the technique of serial dilution, explain how you would make your standards by filling in the chart below. Std 1 Std 2 Std 3 Std 4 concentration (mg/ml) 12 6 3...

  • Experimental sucrose solution (final concentration) 30% 15% Amount of 30% stock sucrose solution needed 5 mL...

    Experimental sucrose solution (final concentration) 30% 15% Amount of 30% stock sucrose solution needed 5 mL 2.5 mL 0.5 mL Amount of water needed O mL 2.5 mL 4.5 mL 3% 12. Make an additional 200 mL of 15% sucrose solution in Beaker 1 by mixing the 30% stock solution with water. Use the following dilution equation to solve for the necessary amount of stock solution MV, = M2V2 Where: • V1 = Needed volume of stock solution M =...

  • Lab 5: Additional Dilution Problems You have a stock solution that contains 24 mg/ml of protein....

    Lab 5: Additional Dilution Problems You have a stock solution that contains 24 mg/ml of protein. You want to make a set of standards with the following concentrations: 12 mg/ml, 6 mg/ml, 3 mg/ml and 1.5 mg/ml You need a minimum of 500 ul of each standard after all dilutions are completed. Using the technique of serial dilution, explain how you would make your standards by filling in the chart below. Std 4 Std 1 12 Std 2 6 Std...

  • Question 7 Working with buffers You need 100 ml of 120 mM phosphate buffer and you have two stock...

    please hlep me answer those three questions asap. Please ignore question 7. Question 7 Working with buffers You need 100 ml of 120 mM phosphate buffer and you have two stock solutions from which you can make the buffer; 0.6 M NaH2PO4 (the acid form) and 0.6 M Na2HP04 (the base form). You need to add 3 times more of the base form than the acid form to achieve the desired pH. How will you make this solution? Question 8...

  • explain question 6 please explain question 8 not 6 Mix 9 mL of water + 1...

    explain question 6 please explain question 8 not 6 Mix 9 mL of water + 1 uL of DNA Mix 1 mL of water+9 mL of DNA QUESTION8 You make a 1:50 dilution of yoqr stock, then you make a 1:10 dilution of the 1:50. What is the dilution factor of the final solution? 1:100 ○ 1:500 1:10 1:5 QUESTION9 0.1 mL Click Save and Submit to save and submit.Click Save All Answers to save all answers Save All Answers...

  • please show work so: 1 ml stock 10 ml final -0.5 mL of stock -5 ml...

    please show work so: 1 ml stock 10 ml final -0.5 mL of stock -5 ml final volume While I have used 1:10 as a standard the same rules apply for all dilution factors. Try these problems: x 0.5 X0.5 1. You need to make a 1:25 dilution factor. If you final volume is 25 mL this means that you need_ _mL of stock and mL of solvent to make your final volume of 25 mL. 2. If you needed...

  • 29. You have the following concentrated commercial reagents on hand; make 1 L of a 6...

    29. You have the following concentrated commercial reagents on hand; make 1 L of a 6 N reagent from each of them. What is the molarity of each concentrated reagent? How to make it? NFLOH sp. gr. = 0.90; 58% assay (V=1) H(CH3C00) sp. gr. = 1.05; 99% assay (v-1) 30. How much 0.02 N HSO, can you make from 200 mL of 4N HSO.? 31. How much Cuso, 8H20 will you need to weigh out to substitute for 120...

  • continued If you have ever peeled the label off of a glass jar, you may have noticed that the gue does not easily w...

    continued If you have ever peeled the label off of a glass jar, you may have noticed that the gue does not easily wash off with water. However, it can be easily removed with another common household solvent-fingernail polish remover (ethyl acetate). What does this tell you about the chemical composition of the gue? Explain your answer. 13 A solution is prepared by dissolving 10.98 g of MgCl, in 646 mL of water. The total mass of the solution is...

  • Given: pH: 7.60 Concentration (M): 0.050 mL: 100mL Determine the Mass of Each Component Recall that...

    Given: pH: 7.60 Concentration (M): 0.050 mL: 100mL Determine the Mass of Each Component Recall that buffers are formed from conjugate acid/base pairs. Using the information given about your assigned buffer, determine how much of each component (acid and base) you will need in order to prepare it in the lab. (This will require a system of equations because there are two “unknowns.”) Note: the conjugate acid in this case is H2PO4−, and the conjugate base is HPO42−. 1. Using...

  • Suppose you have stock solution with a solute concentration of 35 mM. If you wanted to...

    Suppose you have stock solution with a solute concentration of 35 mM. If you wanted to dilute this solution to make a total of 1 ml of a 7 mM solution what volume of stock _____ and what volume of water _____ would you use? Give your answer in micro liters (mu l), and show your calculations. Volume of stock _____ mu l Volume of water ______ mu l

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT