A methods and measurement analyst wants to develop a time standard for a certain task. In...
A methods and measurement analyst wants to develop a time standard for a certain task. In a preliminary study, he observed one worker perform the task six times with an average observed time of 25 seconds and a standard deviation of 3.8 seconds.
What is the standard time for this task if the employee worked at a 15.2 percent faster pace than average, and an allowance of 20.6 percent of the workday is used?
(Keep one decimal place in your answer)
Homework Answers
Average Time = 25 Seconds
Performance Rating = 1+0.152 = 1.152
Normal Tine = Average Time*Performance Rating
Normal Time = 25*1.152 = 28.8 Seconds
Standard Time = Normal Time*(1+Allowance Factor)
Standard Time = 28.8*(1+0.206)
Standard Time = 34.7328 seconds
Standard Time = 34.7 seconds
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