Ammonia can be synthesized according to the equation: N2(g)+2H2(g)<--->2NH3(g) The Kp for this reaction at 725...

Question

Question

Ammonia can be synthesized according to the equation:

N₂_(g)+2H₂_(g)<--->2NH_3(g)

The Kp for this reaction at 725 K is 7.25x10^-5; Calculate Kc at this temperature.

Answer 1

Answer #1

ANSWER:

N₂(g)+2H₂_(g)<--->2NH₃(g)

The problem can be solved by the following equation:

Kp = Kc (RT)^Δn

Δn = (total gaseous products) - (total gaseous reactants) = (2 - 3) = -1

R = gas constant = 8.314 J/Mol K, ;;;; T = Absolute temperature

Kc = Kp / (RT)^Δn = 7.25x10^-5 / (8.314 X 725) ^-1 = 7.25x10^-5 X (8.314 X 725) ⁺¹= 0.44

Answer 2

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