Suppose that the lifetime of a component (in hours), X is modelled with a Weibull distribution with a = 0.6. and λ = 1/4000. Determine the value for P(X > 5,961 | X > 3500) i.e Probability of X > 5,961 given tha X is greater than 3500. Please enter the answer to 3 decimal places.
Suppose that the lifetime of a component (in hours), X is modelled with a Weibull distribution...
Suppose that the lifetime of a component (in hours), X, is modeled with a Weibull distribution with B 0.5 and = 3400. Determine the following in parts (a) and (b) Round your answers to three decimal places (e.g. 98.765) a) P(X> 3500) = i b) P(X> 6000|X > 3000) i c) Suppose that X has an exponential distribution with mean equal to 3400. Determine the following probability Round your answer to three decimal places (e.g. 98.765) P(X 6000X > 3000)...
Suppose that X has a Weibull distribution with B = 0.5 and 8 = 100 hours. Determine the following. Round the answers to 3 decimal places. (a) P(X < 10000) = (b) P(X > 5000) =
The lifetime of bacteria follows the Weibull distribution. The probability that the bacteria lives for more than 10 hours is 0.7 and that it lives more than 20 hours is 0.3. The probability that among 300 bacteria more than 200 live longer than 10 hours can be computed as P(Z>a). What is the value of a?
The lifetime X (in hundreds of hours) of a certain type of vacuum tube has a Weibull distribution with parameters α = 2 and β = 3.Compute the following. (Round your answers to three decimal places.)
Question 4 Lifetime of a certain component can be represented by 2 parameter Weibull distribution with a-12000 and p Find the mean time to failure and median life of this component.
The lifetime of a drill bit in a mechanical operation, in hours, has a Weibull distribution with α = 0.5 and β = 2.2. Calculate the probability that the bit will fail after 2.8 hours Answer using 4 decimals.
The lifetime X (in hundreds of hours) of a certain type of vacuum tube has a Weibull distribution with parameters α = 2 and β = 3. Compute the following.
Suppose that the random variable X has a Weibull distribution with parameters a = 2.98 and λ = 0.23. Find P(3 ≤ X ≤ 7). Round your answer to the nearest ten thousandth.
Suppose that the random variable X has a Weibull distribution with parameters a = 3.68 and λ = 0.21. Find the upper quartile of the distribution. Round your answer to the nearest ten thousandth.
Suppose that the random variable X has a Weibull distribution with parameters a = 4.54 and λ = 0.12. Find the value of X so that F(X)=0.23 where F is the cumulative distribution function. Round your answer to the nearest ten thousandth.