In a random sample of 120 internet users, 45 reported that they had shopped online in...
In a random sample of 120 internet users, 45 reported that they had shopped online in the past week. Find the mean and the standard deviation of the sampling distribution of the sample proportion.
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In a random sample of 120 internet users, 45 reported that they
had shopped online in...
A study reported that 43% of Internet users have searched for information about themselves online. The...
A study reported that 43% of Internet users have searched for information about themselves online. The 43% figure was based on a random sample of Internet users. Suppose that the sample size was n = 500. Construct a 90% confidence interval for the proportion of Internet users who have searched online for information about themselves. (Round your answers to three decimal places.) ( , ) Interpret the interval. We are 90% confident that the proportion of all Internet users who...
A study reported that 48% of Internet users have searched for information about themselves online. The...
A study reported that 48% of Internet users have searched for information about themselves online. The 48% figure was based on a random sample of Internet users. Suppose that the sample size was n = 400. Construct a 90% confidence interval for the proportion of Internet users who have searched online for information about themselves. (Round your answers to three decimal places.) ( , ) Interpret the interval. We are 90% confident that the proportion of all Internet users who...
A study reported that 44% of Internet users have searched for information about themselves online. The...
A study reported that 44% of Internet users have searched for information about themselves online. The 44% figure was based on a random sample of Internet users. Suppose that the sample size was n = 300. Construct a 90% confidence interval for the proportion of Internet users who have searched online for information about themselves. (Round your answers to three decimal places.) ( , ) Interpret the interval. We are confident that the proportion of all Internet users who have...
Questions 15–17. A newspaper reported that 90% of youths use the Internet. Use this reported number...
Questions 15–17. A newspaper reported that 90% of youths use the Internet. Use this reported number as the population proportion. A random sample of 900 youth is selected. Let p be the sample proportion of youths who use the Internet. 15. The distribution of p is closest to ✓(a) normal with mean 0.9 and standard deviation 0.01 (b) normal with mean 0.9 and standard deviation 0.3 (c) binomial with mean 0.9 and standard deviation 0.01 (d) binomial with mean 0.9...
U.S. internet users spend an average of 18.3 hours a week online. If 99% of users...
U.S. internet users spend an average of 18.3 hours a week online. If 99% of users spend between 13.2 and 23.4 hours a week, what is the probability that a randomly selected user is online less than 14 hours a week? Assume that internet usage follows a normal distribution. Round the final answer to four decimal places and intermediate z value calculations to two decimal places. The probability of a randomly selected person being online less that 14 hours per...
A sample survey of 842 adult Internet users found that 67% look for information on the...
A sample survey of 842 adult Internet users found that 67% look for information on the online collaborative encyclopedia Wikipedia. ( a) Give the standard error SE of p̂, the proportion of all adult Internet users who look for information on Wikipedia. (Round your answer to four decimal places.) SE = (b) Give a 95% large sample confidence interval for the proportion of all adult internet users who look for information on Wikipedia. -0.624 to 0.716 -0.615 to 0.725 -0.638...
A random sample of size n = 40 is selected from a binomial distribution with population...
A random sample of size n = 40 is selected from a binomial distribution with population proportion p = 0.25. Describe the approximate shape of the sampling distribution of p̂. approximately normalskewed left uniformskewed right Calculate the mean and standard deviation (or standard error) of the sampling distribution of p̂. (Round your standard deviation to four decimal places.) mean standard deviation Find the probability that the sample proportion p̂ is between 0.15 and 0.41. (Round your answer to four decimal places.)
A random sample is to be selected from a population that has a proportion of successes...
A random sample is to be selected from a population that has a proportion of successes p 0.64. Determine the mean and standard deviation of the sampling distribution of p for each of the following sample sizes. (Round your standard deviations to four decimal places.) (a) n 30 mean standard deviation (b) n 40 mean standard deviation (c) 50 mean standard deviation (d) n- 70 mean standard deviation (e) n-120 mean standard deviation (f) n-220 mean standard deviation
12. An Internet server conducted a survey of 400 of its customers and found that the...
12. An Internet server conducted a survey of 400 of its customers and found that the average amount of time spent online was 12.5 hours per week with a standard deviation of 5.4 hours. What shape do you think the random variable x, the number of hours spent online, has? If the distribution of the original measurements is not normal, you can still use the standard normal distribution to construct a confidence interval for 4, the average online time for...
Selecting a random sample is an example of a statistical experiment, and the sample statistic p i...
Selecting a random sample is an example of a statistical experiment, and the sample statistic p is a numerical description of the result of the experiment. Therefore, p is a random variable. The probability distribution of p is called the sampling distribution of p In practice, you select one random sample and use the information from that sample to estimate the population parameter of interest. However statisticians sometimes perform a procedure called repeated sampling, in which the experiment is run...
Questions 15–17. A newspaper reported that 90% of youths use the Internet. Use this reported number as the population proportion. A random sample of 900 youth is selected. Let p be the sample proportion of youths who use the Internet. 15. The distribution of p is closest to ✓(a) normal with mean 0.9 and standard deviation 0.01 (b) normal with mean 0.9 and standard deviation 0.3 (c) binomial with mean 0.9 and standard deviation 0.01 (d) binomial with mean 0.9...
A random sample is to be selected from a population that has a proportion of successes p 0.64. Determine the mean and standard deviation of the sampling distribution of p for each of the following sample sizes. (Round your standard deviations to four decimal places.) (a) n 30 mean standard deviation (b) n 40 mean standard deviation (c) 50 mean standard deviation (d) n- 70 mean standard deviation (e) n-120 mean standard deviation (f) n-220 mean standard deviation
12. An Internet server conducted a survey of 400 of its customers and found that the average amount of time spent online was 12.5 hours per week with a standard deviation of 5.4 hours. What shape do you think the random variable x, the number of hours spent online, has? If the distribution of the original measurements is not normal, you can still use the standard normal distribution to construct a confidence interval for 4, the average online time for...
Selecting a random sample is an example of a statistical experiment, and the sample statistic p is a numerical description of the result of the experiment. Therefore, p is a random variable. The probability distribution of p is called the sampling distribution of p In practice, you select one random sample and use the information from that sample to estimate the population parameter of interest. However statisticians sometimes perform a procedure called repeated sampling, in which the experiment is run...
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