Write the solubility product constant expression for the solubility of Chromium (III) Hydroxide, Cr(OH)3. What would the solubility in g/100 mL of this salt be in water given the solubility product is 6.1 x 10 ^-31
Cr(OH)3(s) Cr3+(aq) + 3 OH-(aq).
Solubility product constant expression, Ksp = [Cr3+][OH-]3
let solubility of salt is s mol/L. [Cr3+] = s mol/L and [OH-] = 3s mol/L
Ksp = 6.1×10-31 = s × (3s)3 = 27× s4
s = (6.1×10-31 / 27)1/4. = 1.226×10-8mol/L
Molar mass of salt = 103.0181g/mol
Solubility of salt = 1.226×10-8 mol/L × 103.0181g/mol = 1.263×10-6 g/L = 1.263×10-6 g/1000ml
= 1.263×10-7 g/100ml of water.
The solubility of salt = 1.26×10-7 ( in g/100ml) (answer)
Write the solubility product constant expression for the solubility of Chromium (III) Hydroxide, Cr(OH)3. What would...
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