How many moles of solute are contained in each solution?
250mL of a 0.82M Na NO3
Ans :
Number of moles of solute are given as :
moles = molarity x volume of solution (L)
here molarity is 0.82 M
volume = 250 mL = 0.250 L
So putting values :
moles = 0.82 M x 0.250 L
= 0.205 moles
so 0.205 moles of NaNO3 are present in the solution
To determine the number of moles of solute in a solution, you can use the formula:
moles = concentration (M) × volume (L)
Given: Concentration (M) = 0.82 M Volume (mL) = 250 mL
First, convert the volume from milliliters (mL) to liters (L): Volume (L) = 250 mL ÷ 1000 = 0.250 L
Now we can calculate the number of moles of solute: moles = 0.82 M × 0.250 L = 0.205 mol
Therefore, there are 0.205 moles of NaNO3 in the given solution.
How many moles of solute are contained in each solution? 250mL of a 0.82M Na NO3
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