In humans, with the trait for interlaced fingers, left thumb over right is dominant (L), and...
In humans, with the trait for interlaced fingers, left thumb over right is dominant (L), and right over left is recessive (l). A man with the dominant trait for interlaced fingers marries a woman with the dominant trait for interlaced fingers and their children all have the recessive trait. What chance did each child have for interlaced fingers?
Homework Answers
left thumb over right is dominant (L), and right over left is recessive (l).
both parents have dominant traits but the their children have recessive traits so the genotype of the parents is heterozygous.
Ll * Ll
| L | l | |
| L | LL | Ll |
| l | Ll | ll |
the phenotype of the children is recessive, that is right thumb over left so their genotype is ll,
so chance that each child have the recessive trait= number of ll/total number=1/4
the chance that each child have for interlaced fingers=1/4
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